Aptitude - Percentage - Discussion

Easy way :

Here as give in problem,

He buys the goods worth Rs..6650.
He gets rebate of 6%.
i.e discount of 6%.

So now 6% of 6650rs = (6*6650)/100.
= 399 rs..(discounted amount).

After removing the discount he has to pay :
6650 - 399 = 6251 rs.

As given, he will pay a tax of 10%,
i.e sales tax = 10% of 6251.
= (10*6251)/100,
= 625.10 rs.

So now, the amount to be paid = 6252 + 625.10.
= 6876.10 rs.

Let assume.
100------------>6650
94------------->? (6%he gets a rebate(discount)so,we deduct6%).

Then,94*6650/100=6251.

After that,he pays 10%on sales tax.

So,100------------->6251(after rebate total money)
110------------->?(including 10% tax).


Then,110*6251/100==>687610/100=6876.10.

He will have to pay for the goods Rs.6876.10.

A candidate score 25% and fail by 30 marks, while another candidate score 50% marks, get 20% marks more than minimum required marks to pass the examination. Find the maximum marks for the examination and pass marks.

Can any one solve this question? And explain.

Easily,

He bought goods for Rs.6650 and he got 6%refund and he pays 10% tax from the cost of the goods.
So, 10% - 6% = 4% (i.e he needs to pay 4% of 6650).

4% of 6650 = 226( this much he need to pay in addition to the cost 6650)
Therefore, 6650 + 226 = 6876.

Rajesh brought a TV priced at Rs 2000. He was given two Successive discounts of 10 and 5 percent. If he has to pay percent sales tax, the net amount he paid was

a) Rs 2663.40
b) Rs 2660
c) Rs 2350
d) Rs 2460

How to solve this question?

If he got an item of 6650 then 6% i.e. 6/100= 3/50.
This means in 50 units 3 units less in 50 as rebate = 47/50 rebate.
Same way if 10% sales tax then 1/10 means 1 unit more paid in 10 = 11/10.
Therefore, 6650 * 47/50 * 11/10 = 6876.1.

A = 150% of B = 150/100*B = 3/2B.

C = 120% of A = 120/100*A = 6/5A = 6/5*3/2B = 9/5B.

A+B+C = 86000.

3/2B+B+9/5B = 86000.

43B/10 = 86000.

So B = 20000.

3/2*20000+20000+C = 86000.

C = 86000-50000 = 36000 OR C = 9/5*20000 = 36000.

@Saqlain.
Let x be maximum no.of marks and y be minimum marks.
25x/100=y-30 .......(1).

x/2 = y+(20 * y/100).

x/2 = 6y/5......(2).

From 1 x/4 = y-30.
(x/2) * 1/2 = y-30.
(6y/5) * 1/2 = y-30.
3y = 5y-150.
y = 75.
x = 180.

@Pinki.

I think answer is 50 cc.

Salt : water.

Initial 1:1.
After 1:3.

So net water added=3-1=2 part.

Here initial volume is given 50 cc.

So 2 part = 50 cc.

Net water added = 50 cc.

I hope you understand.

The income of A is 150% of the income of B and the income of C is 120% of the income of A. If the total income of A, B and C together is Rs. 86,000, what is C's income?
1. 30,000
2. 32,000
3. 20,000
4. 36,000