Aptitude - Odd Man Out and Series - Discussion
Discussion Forum : Odd Man Out and Series - Pick Wrong No. (Q.No. 5)
Directions to Solve
Find out the wrong number in the given sequence of numbers.
5.
1, 2, 6, 15, 31, 56, 91
Answer: Option
Explanation:
1, 1 + 12 = 2, 2 + 22 = 6, 6 + 32 = 15, 15 + 42 = 31, 31 + 52 = 56, 56 + 62 = 92
Last number of given series must be 92 not 91.
Discussion:
22 comments Page 1 of 3.
Utkarsh Kumar said:
7 years ago
2 is also a prime number. So 31 cannot be the answer even if we consider this question in terms of prime numbers.
This question is solved on the basis of perfect squares. Subtract each adjacent number and you will get a perfect square, except:
91-56 = 35.
35 is not a perfect square, so we make it 36 by adding 1 to 91. Thus the final series will be as follows:
1, 2, 6, 15, 31, 56, 92
where subtracting any two adjacent numbers will give a perfect square.
I hope this helps.
This question is solved on the basis of perfect squares. Subtract each adjacent number and you will get a perfect square, except:
91-56 = 35.
35 is not a perfect square, so we make it 36 by adding 1 to 91. Thus the final series will be as follows:
1, 2, 6, 15, 31, 56, 92
where subtracting any two adjacent numbers will give a perfect square.
I hope this helps.
(9)
Sikkanthar said:
1 decade ago
In this problem they are adding the result with square value of the natural numbers.
I mean.
1,
1(result) + (1*1) = 2.
2(result) + (2*2) = 6.
6(result) + (3*3) = 15.
15(result) + (4*4) = 31.
31(result) + (5*5) = 56.
56(result) + (6*6) = 92.
Now we are getting 92 not 91.. So 91 is the wrong number of the given.
I mean.
1,
1(result) + (1*1) = 2.
2(result) + (2*2) = 6.
6(result) + (3*3) = 15.
15(result) + (4*4) = 31.
31(result) + (5*5) = 56.
56(result) + (6*6) = 92.
Now we are getting 92 not 91.. So 91 is the wrong number of the given.
Ravi Agola said:
1 decade ago
Actual answer by easy method.
1 is odd then two are even 2, 6 then two are odd 15, 31 then two are even 56, 91 but here 91 is odd so answer. Is 91 which we same get with previous method.
1 is odd then two are even 2, 6 then two are odd 15, 31 then two are even 56, 91 but here 91 is odd so answer. Is 91 which we same get with previous method.
(1)
Rajesh said:
1 decade ago
@Kumar.
Your concept is OK. But same time you took the wrong concept.
First minus 1 by 2.
Then minus 6 by 2 how is it correct? OK now you understand.
But your thing is good.
Your concept is OK. But same time you took the wrong concept.
First minus 1 by 2.
Then minus 6 by 2 how is it correct? OK now you understand.
But your thing is good.
Sam said:
1 decade ago
10 teams participating in national football league. If each team plays the other team two times, the total number of games the league will play is.
Arthy said:
9 years ago
2 - 1 = 1(odd),
6 - 2 = 4(even),
15 - 6 = 9(odd),
31 - 15 = 16(even),
56 - 31= 25(odd),
But 91 - 56 = 45 (odd) so that 91 is the wrong number here.
6 - 2 = 4(even),
15 - 6 = 9(odd),
31 - 15 = 16(even),
56 - 31= 25(odd),
But 91 - 56 = 45 (odd) so that 91 is the wrong number here.
(6)
Sonutalwani said:
1 decade ago
1 + (1*1) = 2.
2 + (2*2) = 6.
6 + (3*3) = 15.
15 + (4*4) = 31.
31 + (5*5) = 56.
56 + (6*6) = 92 (91 is wrong number).
2 + (2*2) = 6.
6 + (3*3) = 15.
15 + (4*4) = 31.
31 + (5*5) = 56.
56 + (6*6) = 92 (91 is wrong number).
Kumar said:
1 decade ago
2-1,6-2,15-6,31-15,56-31,91-56
1,4,9,16,25,45
last number is clearly wrong because those are perfect squares
1,4,9,16,25,45
last number is clearly wrong because those are perfect squares
Umang said:
1 decade ago
2-1 = 1*1
6-2 = 2*2
15-6 = 3*3
31-15 = 4*4
64-31 = 5*5
But 91-56 = 6*6 is not happening.
So 91 is odd no.
6-2 = 2*2
15-6 = 3*3
31-15 = 4*4
64-31 = 5*5
But 91-56 = 6*6 is not happening.
So 91 is odd no.
Riya said:
1 decade ago
According to me 31 should be the answer because its the only prime no in the question?
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