Aptitude - Odd Man Out and Series - Discussion
Discussion Forum : Odd Man Out and Series - Odd Man Out (Q.No. 4)
Directions to Solve
Find the odd man out.
4.
396, 462, 572, 427, 671, 264
Answer: Option
Explanation:
In each number except 427, the middle digit is the sum of other two.
Discussion:
50 comments Page 4 of 5.
Gopal said:
1 decade ago
All the numbers except 427 are multiple of 11.
Sonutalwani said:
1 decade ago
3+9+6=18 even.
4+6+2=12 even.
5+7+2=14 even.
4+2+7=13 odd.
4+6+2=12 even.
5+7+2=14 even.
4+2+7=13 odd.
Swetha said:
1 decade ago
Except 427 every number is divisible by 11.
Ashish said:
1 decade ago
Just check the divisibility rule of 2. All digits are divisible by 2 except 671. So why not 671?
Suresh said:
1 decade ago
May be @Swetha and @Gopal is right. But @Ashish's answer is not perfect. Because 427 is not divisible by 2. I can't accept the answer given by the internet.
Thulasi said:
1 decade ago
Out of the four options 427 is not divisible by 3.
Pavan said:
1 decade ago
Sum of first and last number equal to the middle number except 427.
Sravya said:
1 decade ago
Sum of all digits are even except 427.
4+2+7=13 odd num.
So 427 is odd one. From the given series.
4+2+7=13 odd num.
So 427 is odd one. From the given series.
Mukesh said:
1 decade ago
There is another method to solve this which is that the sum of all the digits of a number except 427 is even.
Krishna said:
1 decade ago
Sum digit is even number in the given option except 427.
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