Aptitude - Odd Man Out and Series - Discussion
Discussion Forum : Odd Man Out and Series - Odd Man Out (Q.No. 4)
Directions to Solve
Find the odd man out.
4.
396, 462, 572, 427, 671, 264
Answer: Option
Explanation:
In each number except 427, the middle digit is the sum of other two.
Discussion:
50 comments Page 4 of 5.
Shubhankar shukla said:
1 decade ago
The sum of all the numbers is divisible by 2 except 427.
D.nandhini said:
1 decade ago
Answer may also 396 because there is no number having 9 in the middle.
Arnab said:
1 decade ago
427 is not divided by 11. Other numbers are divided by 11.
Pavan said:
1 decade ago
Why not 671 as the other all is evens?
Sony said:
1 decade ago
Subtract second integer from first integer we get sum.
For ex:-
572 = 7-5 = 2;
462 = 6-4 = 2;
Like this.
For ex:-
572 = 7-5 = 2;
462 = 6-4 = 2;
Like this.
Krishna said:
1 decade ago
Sum digit is even number in the given option except 427.
AGHIL said:
1 decade ago
The number in the middle or ten's place is the sum of the other two digits.
572 = 5+2 = 7.
462 = 4+2 = 6 so on..
But 427 is not applicable. So it is odd.
572 = 5+2 = 7.
462 = 4+2 = 6 so on..
But 427 is not applicable. So it is odd.
Sravya said:
1 decade ago
Sum of all digits are even except 427.
4+2+7=13 odd num.
So 427 is odd one. From the given series.
4+2+7=13 odd num.
So 427 is odd one. From the given series.
Pavan said:
1 decade ago
Sum of first and last number equal to the middle number except 427.
Thulasi said:
1 decade ago
Out of the four options 427 is not divisible by 3.
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