Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 13)
13.
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
Answer: Option
Explanation:
Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
Discussion:
57 comments Page 5 of 6.
Abhishek Gupta said:
7 years ago
I can't understand this question, anyone can help me to solve this problem, please.
Vishan Dogra said:
7 years ago
Larger no is y.
y-x= 1365 ---> 1.
Divident =divisor * q+R.
y=x * 6 + 15,
Y=6x + 15 ---> 2
Substitute the value of eq 2 in 1.
6x + 15 - x = 1365,
5x + 15 = 1365,
5x = 1365-15,
x = 1350/5 = 270.
y-x= 1365 ---> 1.
Divident =divisor * q+R.
y=x * 6 + 15,
Y=6x + 15 ---> 2
Substitute the value of eq 2 in 1.
6x + 15 - x = 1365,
5x + 15 = 1365,
5x = 1365-15,
x = 1350/5 = 270.
Bharath said:
7 years ago
Dividend = (divisor * quotient) + remainder.
Let the smaller number be x.
Then larger number = (x + 1365).
On dividing larger number by smaller number.
=> (x+1365)/x.
x + 1365 = 6x + 15,
5x = 1350,
x = 270.
Smaller number = 270.
Let the smaller number be x.
Then larger number = (x + 1365).
On dividing larger number by smaller number.
=> (x+1365)/x.
x + 1365 = 6x + 15,
5x = 1350,
x = 270.
Smaller number = 270.
(2)
Paimon Dkhar said:
7 years ago
X is the smaller and y is the larger.
Y=x+1365,
Y=270+1365,
Y=1635.
Larger divided by a smaller number.
=1635/270.
Here I got 6 quotient & 15 Remainder.
Yes, 270 is the smaller number.
Y=x+1365,
Y=270+1365,
Y=1635.
Larger divided by a smaller number.
=1635/270.
Here I got 6 quotient & 15 Remainder.
Yes, 270 is the smaller number.
(1)
Pooja said:
6 years ago
Let the smaller number be= x.
Then the larger number be= x+1365.
We already have,
Quotient = 6,
Remainder= 15,
Divisor = x ( as in every division divisor is smaller than the dividend),
Dividend = x+1365.
As per formula,
Divisor = (dividend-remainder)/quotient.
=> x = (x+1365-15)/6,
=> x = (x+1350)/6,
=> 6x-x = 1350,
=> 5x = 1350,
=> x = 1350/5,
=> x = 270 (the smaller number) (answer).
Then the larger number be= x+1365.
We already have,
Quotient = 6,
Remainder= 15,
Divisor = x ( as in every division divisor is smaller than the dividend),
Dividend = x+1365.
As per formula,
Divisor = (dividend-remainder)/quotient.
=> x = (x+1365-15)/6,
=> x = (x+1350)/6,
=> 6x-x = 1350,
=> 5x = 1350,
=> x = 1350/5,
=> x = 270 (the smaller number) (answer).
(4)
Anudeep gajjala said:
5 years ago
Good explanation, Thanks @Jomon.
Sania prathi said:
5 years ago
Nice explanation @Jomon.
Aishwarya said:
5 years ago
@All.
Lets consider smaller number as X --->(i)
As per given difference of two numbers is 1365.
So consider larger number as X+1365 ---> (ii).
Dividend = quotient * divisor + remainder.
On dividing larger number by smaller number just put given values in above formula.
So we got equation as:
X+1365 = 6 * X + 15
5X = 1350.
X = 270 is smaller number.
Lets consider smaller number as X --->(i)
As per given difference of two numbers is 1365.
So consider larger number as X+1365 ---> (ii).
Dividend = quotient * divisor + remainder.
On dividing larger number by smaller number just put given values in above formula.
So we got equation as:
X+1365 = 6 * X + 15
5X = 1350.
X = 270 is smaller number.
(5)
Uma said:
5 years ago
Perfect and good explanation Thanks @Bharath.
(4)
Uma said:
5 years ago
Let us assume the largest number is X & the Smallest number is Y.
The difference between two number is 1365.
So, X - Y=1365
X=1365+Y------------(1).
Now, assume the largest number is dividend, the smaller number is divisior
So, X is dividend & Y is divisior.
We know that,
Dividend= divisior*quostient + remainder.
X = Y * 6 + 15.
X = 6Y + 15------------> (2).
Let substitute eq(1) in eq(2).
1365 + Y = 6Y + 15.
Y - 6Y = 15 - 1365.
- 5Y = - 1350.
Here minus(-) minus(-) gets cancel.
So, 5Y = 1350.
Y= 1350/5.
Y=270.
The difference between two number is 1365.
So, X - Y=1365
X=1365+Y------------(1).
Now, assume the largest number is dividend, the smaller number is divisior
So, X is dividend & Y is divisior.
We know that,
Dividend= divisior*quostient + remainder.
X = Y * 6 + 15.
X = 6Y + 15------------> (2).
Let substitute eq(1) in eq(2).
1365 + Y = 6Y + 15.
Y - 6Y = 15 - 1365.
- 5Y = - 1350.
Here minus(-) minus(-) gets cancel.
So, 5Y = 1350.
Y= 1350/5.
Y=270.
(21)
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