Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 13)
13.
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
Answer: Option
Explanation:
Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
Discussion:
57 comments Page 1 of 6.
Pratyush Sharma said:
5 months ago
Difference of two numbers:
a- b = 1365.
a/b = 6 15/b.
a - b means 1 times of a is reduced from b and 15 extra part is remaining.
Also it is given that 6 times of b is leaving 15 as remainder;
So in a - b we only have 5 times b + 15.
Thus 1365-15/5 is the smallest number.
1365-15/5= 270.
For example
If a = 117 b = 17,
a-b = 100,
6b = 102,
5b = 85,
a/b leaves remainder 15.
So, a-b-15=85 which is equal to 5b.
a- b = 1365.
a/b = 6 15/b.
a - b means 1 times of a is reduced from b and 15 extra part is remaining.
Also it is given that 6 times of b is leaving 15 as remainder;
So in a - b we only have 5 times b + 15.
Thus 1365-15/5 is the smallest number.
1365-15/5= 270.
For example
If a = 117 b = 17,
a-b = 100,
6b = 102,
5b = 85,
a/b leaves remainder 15.
So, a-b-15=85 which is equal to 5b.
(1)
Kumaran said:
6 months ago
225 is the correct answer.
1365 - 15 = 1350.
So, 225 * 6 is 1350, and the remainder is 15. So, kindly calculate the sum with the answer.
1365 - 15 = 1350.
So, 225 * 6 is 1350, and the remainder is 15. So, kindly calculate the sum with the answer.
(2)
Sundar said:
1 year ago
Thanks for explaining the answer @Pooja.
Ajay said:
1 year ago
Let us assume x as smaller number and y as the bigger one.
So, from the question,
y-x = 1365 --->1
y = 1365 + x --->2
From question,
y/x = 6 --->3
Gives, y = 6x. --->4
Sub 4 in 1,
6x - x = 1365
x = 273.
(Since leaves remainder 15 which is 5 ×3 =15. So, subtracting 3 from 273 to get the number that leaves no remainder)
So the number that leaves no remainder is 270.
So, from the question,
y-x = 1365 --->1
y = 1365 + x --->2
From question,
y/x = 6 --->3
Gives, y = 6x. --->4
Sub 4 in 1,
6x - x = 1365
x = 273.
(Since leaves remainder 15 which is 5 ×3 =15. So, subtracting 3 from 273 to get the number that leaves no remainder)
So the number that leaves no remainder is 270.
(15)
Pratyush Sharma said:
2 years ago
Let Y is the larger Number and X is the smaller Number.
The difference between X and Y is 1365.
Also, 6 times X is equal to Y - 15.
So, if we subtract 15 more from 1365 we get the difference of 6 times X and X as :
6X - X = 1365-15.
X = 270.
Y = 1635.
The difference between X and Y is 1365.
Also, 6 times X is equal to Y - 15.
So, if we subtract 15 more from 1365 we get the difference of 6 times X and X as :
6X - X = 1365-15.
X = 270.
Y = 1635.
(4)
Srikanth said:
4 years ago
Let's assume;
x is the larger number.
y is smaller number.
x - y = 1365
x/y = 6
x = 6 * y + 15,
6 * y + 15 - y = 1365.
y = 270.
x is the larger number.
y is smaller number.
x - y = 1365
x/y = 6
x = 6 * y + 15,
6 * y + 15 - y = 1365.
y = 270.
(42)
Bhushan J said:
5 years ago
Let smaller no x.
Larger no x + 1365.
Quotient = 6.
Remainder = 15
Divisor = x + 1365,.
Dividend = x,
Dividend = divisor * quotient + remainder.
x + 1365 = x * 6 + 15,
1350 = 5x,
x = 270.
Larger no x + 1365.
Quotient = 6.
Remainder = 15
Divisor = x + 1365,.
Dividend = x,
Dividend = divisor * quotient + remainder.
x + 1365 = x * 6 + 15,
1350 = 5x,
x = 270.
(16)
Uma said:
5 years ago
Let us assume the largest number is X & the Smallest number is Y.
The difference between two number is 1365.
So, X - Y=1365
X=1365+Y------------(1).
Now, assume the largest number is dividend, the smaller number is divisior
So, X is dividend & Y is divisior.
We know that,
Dividend= divisior*quostient + remainder.
X = Y * 6 + 15.
X = 6Y + 15------------> (2).
Let substitute eq(1) in eq(2).
1365 + Y = 6Y + 15.
Y - 6Y = 15 - 1365.
- 5Y = - 1350.
Here minus(-) minus(-) gets cancel.
So, 5Y = 1350.
Y= 1350/5.
Y=270.
The difference between two number is 1365.
So, X - Y=1365
X=1365+Y------------(1).
Now, assume the largest number is dividend, the smaller number is divisior
So, X is dividend & Y is divisior.
We know that,
Dividend= divisior*quostient + remainder.
X = Y * 6 + 15.
X = 6Y + 15------------> (2).
Let substitute eq(1) in eq(2).
1365 + Y = 6Y + 15.
Y - 6Y = 15 - 1365.
- 5Y = - 1350.
Here minus(-) minus(-) gets cancel.
So, 5Y = 1350.
Y= 1350/5.
Y=270.
(21)
Uma said:
5 years ago
Perfect and good explanation Thanks @Bharath.
(4)
Aishwarya said:
5 years ago
@All.
Lets consider smaller number as X --->(i)
As per given difference of two numbers is 1365.
So consider larger number as X+1365 ---> (ii).
Dividend = quotient * divisor + remainder.
On dividing larger number by smaller number just put given values in above formula.
So we got equation as:
X+1365 = 6 * X + 15
5X = 1350.
X = 270 is smaller number.
Lets consider smaller number as X --->(i)
As per given difference of two numbers is 1365.
So consider larger number as X+1365 ---> (ii).
Dividend = quotient * divisor + remainder.
On dividing larger number by smaller number just put given values in above formula.
So we got equation as:
X+1365 = 6 * X + 15
5X = 1350.
X = 270 is smaller number.
(5)
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