Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 13)
13.
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
Answer: Option
Explanation:
Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
Discussion:
57 comments Page 3 of 6.
Tejas said:
8 years ago
Difference between two natural nos is 23. If we get quotient 2 on dividing the bigger no by the smaller no then find the nos.
Smooth kill said:
8 years ago
It's simple.
lets take the larger number = (x) and smaller number = (y)
the difference between them is 1365
x-y = 1365 ---------- equation 1.
we know dividend = quotient * divisor + remainder
here the larger number is divided by smaller number
hence we get ,
6x + 15 = y
arranging it we get
6x - y = -15 ----------- equation 2.
adding both equation and solving them we get
y = 270.
lets take the larger number = (x) and smaller number = (y)
the difference between them is 1365
x-y = 1365 ---------- equation 1.
we know dividend = quotient * divisor + remainder
here the larger number is divided by smaller number
hence we get ,
6x + 15 = y
arranging it we get
6x - y = -15 ----------- equation 2.
adding both equation and solving them we get
y = 270.
Udit said:
7 years ago
@Seema.
6 is quotient.
6 is quotient.
Abhishek Gupta said:
7 years ago
I can't understand this question, anyone can help me to solve this problem, please.
Vishan Dogra said:
7 years ago
Larger no is y.
y-x= 1365 ---> 1.
Divident =divisor * q+R.
y=x * 6 + 15,
Y=6x + 15 ---> 2
Substitute the value of eq 2 in 1.
6x + 15 - x = 1365,
5x + 15 = 1365,
5x = 1365-15,
x = 1350/5 = 270.
y-x= 1365 ---> 1.
Divident =divisor * q+R.
y=x * 6 + 15,
Y=6x + 15 ---> 2
Substitute the value of eq 2 in 1.
6x + 15 - x = 1365,
5x + 15 = 1365,
5x = 1365-15,
x = 1350/5 = 270.
Rahul said:
9 years ago
@Jomon.
Good explanation, thanks.
Good explanation, thanks.
Sundar said:
1 year ago
Thanks for explaining the answer @Pooja.
Sania prathi said:
5 years ago
Nice explanation @Jomon.
Anudeep gajjala said:
5 years ago
Good explanation, Thanks @Jomon.
Abhijeet Patil said:
1 decade ago
x = larger number.
y = smaller number.
Given that,
x-y = 1365...... (1).
x/y = 6.
x = 6y+15.
x-6y = 15....... (2).
Solving eq 1 and 2.
x-6y = 15
-x+y = -1365
_____________
-5y= -1365
y = 270.
y = smaller number.
Given that,
x-y = 1365...... (1).
x/y = 6.
x = 6y+15.
x-6y = 15....... (2).
Solving eq 1 and 2.
x-6y = 15
-x+y = -1365
_____________
-5y= -1365
y = 270.
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