Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 27)
27.
On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
Answer: Option
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R.
Discussion:
181 comments Page 8 of 19.
B aparna said:
1 decade ago
Let the number be X.
On dividing X by 56 we get remainder 29.
That means X-29 is divisible by 56.
Co primes for 56 are 7, 8 that means 7*8 = 56.
So X-29 is divisible by 7 and 8.
That mean X-29/8 gives a reminder 0.
This means X/8 remainder-29/8 remainder =0.
X/8 remainder - 5 = 0.
X/8 remainder = 5.
On dividing X by 56 we get remainder 29.
That means X-29 is divisible by 56.
Co primes for 56 are 7, 8 that means 7*8 = 56.
So X-29 is divisible by 7 and 8.
That mean X-29/8 gives a reminder 0.
This means X/8 remainder-29/8 remainder =0.
X/8 remainder - 5 = 0.
X/8 remainder = 5.
Shivani Gupta said:
1 decade ago
56 is simply divided by 8 and get 0, so whatever we multiply with it it will be divisible by 0. Now reminder value divide by 8.
29 % 8 = 5 (we get 5 as remainder).
So the answer is 5.
29 % 8 = 5 (we get 5 as remainder).
So the answer is 5.
Nehaagra26211 said:
1 decade ago
When same number is divided by two different divisors such that one divisor is multiple of another divisor and the remainder R of greater is known then remainder is given by (R/d).
Munish said:
1 decade ago
x = 56*y + 29.
= 7*8*y + 3*8 + 5.
The remainder is 5 ie (B).
= 7*8*y + 3*8 + 5.
The remainder is 5 ie (B).
Balaji Shinde, Kurduwadi said:
1 decade ago
56+29 = 85.
85/8 so we get the remainder 5.
85/8 so we get the remainder 5.
Prasanna Kumar said:
1 decade ago
8)29(3
24
-------
5
-------
This is the simplest way to solve.
In less time we can get answer.
24
-------
5
-------
This is the simplest way to solve.
In less time we can get answer.
P.Chandra Sekhar said:
1 decade ago
Read carefully and then understand.
Let us consider that the number divisible by 56 and leaves a remainder 29 be x+29. When the same number is divided by 8 definitely the x is divisible by 8 since it is divisible 56 and 56 is divisible 8 now we should take care about 29. When 29 is divided by 8 it leaves the remainder 5.
So the answer is 5.
Let us consider that the number divisible by 56 and leaves a remainder 29 be x+29. When the same number is divided by 8 definitely the x is divisible by 8 since it is divisible 56 and 56 is divisible 8 now we should take care about 29. When 29 is divided by 8 it leaves the remainder 5.
So the answer is 5.
M.Nagasai Babu said:
1 decade ago
This is simple question. Take any example.
56*1 = 56.
But it should leave 29 as remainder. So 56+29=85.
Let divide 85 with 8. Then get answer.(85%8=5).
56*1 = 56.
But it should leave 29 as remainder. So 56+29=85.
Let divide 85 with 8. Then get answer.(85%8=5).
Abhi said:
1 decade ago
Given number is 56 and 56 is a multiple of 8 so every no divided.
By 56 is also divisible by 8 hence.
The remainder i.e. 29.
29/8 gives Remainder 5.
Hence 5.
By 56 is also divisible by 8 hence.
The remainder i.e. 29.
29/8 gives Remainder 5.
Hence 5.
Praneeth said:
1 decade ago
This is the simplest way of all.
Since a number is divisible by 56 and gives remainder as 29.
Let the least possible number that satisfies the above condition,
So the number is = (56+29) ;
Number = 85;
(if you want just check it, 85%56 = 29).
So the same number 85%8 = 5 (as stated in the question).
As simple as that.
Since a number is divisible by 56 and gives remainder as 29.
Let the least possible number that satisfies the above condition,
So the number is = (56+29) ;
Number = 85;
(if you want just check it, 85%56 = 29).
So the same number 85%8 = 5 (as stated in the question).
As simple as that.
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