Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 27)
27.
On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
Answer: Option
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R.
Discussion:
181 comments Page 12 of 19.
B aparna said:
1 decade ago
Let the number be X.
On dividing X by 56 we get remainder 29.
That means X-29 is divisible by 56.
Co primes for 56 are 7, 8 that means 7*8 = 56.
So X-29 is divisible by 7 and 8.
That mean X-29/8 gives a reminder 0.
This means X/8 remainder-29/8 remainder =0.
X/8 remainder - 5 = 0.
X/8 remainder = 5.
On dividing X by 56 we get remainder 29.
That means X-29 is divisible by 56.
Co primes for 56 are 7, 8 that means 7*8 = 56.
So X-29 is divisible by 7 and 8.
That mean X-29/8 gives a reminder 0.
This means X/8 remainder-29/8 remainder =0.
X/8 remainder - 5 = 0.
X/8 remainder = 5.
Praveena said:
1 decade ago
Take any multiple of 56.
Lets say,
56*2=112 and as the remainder is 29 add it to 112 so it will sum up to 141 now divide it with 8, then remainder will be 8.
Lets say,
56*2=112 and as the remainder is 29 add it to 112 so it will sum up to 141 now divide it with 8, then remainder will be 8.
Sanjayj singh said:
1 decade ago
Division is similar to subtraction in which numerator is greater than denominator,
So in this case
Number= 56*a+29.
So dividing this number by 8 means
56*a / 8 is completely dividable.
And 29= 8*3+5
So 5 will be remaining.
So in this case
Number= 56*a+29.
So dividing this number by 8 means
56*a / 8 is completely dividable.
And 29= 8*3+5
So 5 will be remaining.
P.sairam said:
1 decade ago
If we take a number which is divisible by 56 having reminder 29.
I take 141/56 it give 29 reminder.
Now the same number is divided by 8 it will give reminder as 5.
I take 141/56 it give 29 reminder.
Now the same number is divided by 8 it will give reminder as 5.
Rahul said:
1 decade ago
Let number be : 56*1+29=85.
When 85 divided by 8. Remainder is 5.
Similarly,
56*2+29=141.
141/8, gives 5 remainder.
When 85 divided by 8. Remainder is 5.
Similarly,
56*2+29=141.
141/8, gives 5 remainder.
Syed Thousif said:
1 decade ago
Let us take the number as X and we know divisor is 56 and the remainder is 29. Therefore , for instance lets consider the following math,
56 ) X ( 2
112
------
29
------
Which means X - 112 = 29. Therefore X = 112+29 = 141.
Now divide 141 with 8.
The remainder is 5.
56 ) X ( 2
112
------
29
------
Which means X - 112 = 29. Therefore X = 112+29 = 141.
Now divide 141 with 8.
The remainder is 5.
Ashish kumar said:
1 decade ago
Let X be the number.
According to the formula,
Divisor = dividend-remainder/quotient.
Putting all in formula.
56 = x-29.
x = 85.
Now we got the number therefore dividing it by 8.
We get Remainder as 5 That's the Answer.
According to the formula,
Divisor = dividend-remainder/quotient.
Putting all in formula.
56 = x-29.
x = 85.
Now we got the number therefore dividing it by 8.
We get Remainder as 5 That's the Answer.
Alok singh said:
1 decade ago
Let x be the number.
Then, x = 56k + 29 = 56k + 24 + 5 = 8(7k + 3) + 5
Hence remainder will be 5.
Then, x = 56k + 29 = 56k + 24 + 5 = 8(7k + 3) + 5
Hence remainder will be 5.
Ramya said:
1 decade ago
If the remainder is again divided by 8 the remainder is 5.
29 / 8 = 3 remainder 5
29 / 8 = 3 remainder 5
Pawan said:
1 decade ago
Actually,
Number= (k*56+29).
Number= (k*56+24+5).
Number=8* (k*7+3) +5.
So divided number by 8, We get reminder 5.
Number= (k*56+29).
Number= (k*56+24+5).
Number=8* (k*7+3) +5.
So divided number by 8, We get reminder 5.
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