Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 27)
27.
On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
Answer: Option
Explanation:
Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R.
Discussion:
181 comments Page 11 of 19.
Sudhakar.batti said:
1 decade ago
Let the number be x, so when x is divisible by 56 the remainder is 29.
56*y+29 = x.
When it is divided by 8.x/8 = 56*y/8+29/8.
When 29 is divided by 8 remainder will be 5.
56*y+29 = x.
When it is divided by 8.x/8 = 56*y/8+29/8.
When 29 is divided by 8 remainder will be 5.
Bhushan said:
1 decade ago
If any no. X divisible by another no Y then any no. divisible by X , will also divisible by Y and all factors of Y.
Here, X be any no divisible by 56 and 56 is divisible by 8 and 8 is factor of 56. that why we use,
Number = (k*56+29).
Number = (k*56+24+5).
Number = 8* (k*7+3) +5.
So divided number by 8, We get reminder 5.
Here, X be any no divisible by 56 and 56 is divisible by 8 and 8 is factor of 56. that why we use,
Number = (k*56+29).
Number = (k*56+24+5).
Number = 8* (k*7+3) +5.
So divided number by 8, We get reminder 5.
Dhaval Chevli said:
1 decade ago
Take 56 + 29 = 85 as the number.
Now divide 85 by 8, then you get 5 as answer.
Now divide 85 by 8, then you get 5 as answer.
Ravi Kumar said:
1 decade ago
Let the number is x and the quotient is y.
So as per the Euclidean Algorithm.
x = 56*y + 29.
Now Splitting it into multiples of 8.
x = 8 * 7 * y + 8*3 + 5.
Taking 8 common from the above equation.
x = 8(7y+3) + 5.
So we get 5 at the remainder place as per Euclidean Algorithm. So the correct answer is 5.
So as per the Euclidean Algorithm.
x = 56*y + 29.
Now Splitting it into multiples of 8.
x = 8 * 7 * y + 8*3 + 5.
Taking 8 common from the above equation.
x = 8(7y+3) + 5.
So we get 5 at the remainder place as per Euclidean Algorithm. So the correct answer is 5.
Narendra said:
1 decade ago
Let x be the number and y be the quotient. Then,
x = 56 x y + 29.
= (8 x 7 x y) + (8 x 3) + 5.
= 8 x (7y + 3) + 5).
Required remainder = 5.
x = 56 x y + 29.
= (8 x 7 x y) + (8 x 3) + 5.
= 8 x (7y + 3) + 5).
Required remainder = 5.
Thurpu Sucharitha said:
1 decade ago
x = 56k+29 then x = 8k+?
By solving.. k = (x-29)/56.
Then x = 24+5.
Remainder is 5.
By solving.. k = (x-29)/56.
Then x = 24+5.
Remainder is 5.
Prashant Chavan said:
1 decade ago
56 is divisible by 8 so any number divisible by 56 is also divisible by 8 so consider only reminder i.e 29 divide the reminder by 8 i.e 29/8 we will get reminder 5 so answer is 5.
Ashvini said:
1 decade ago
Suppose number is x then,
(x-29)/56 = 0 ..... 1.
x/8 = ? .... 2.
From 1 we get x = 29.
Put these value in 2.
29/8 = 5 answer.
(x-29)/56 = 0 ..... 1.
x/8 = ? .... 2.
From 1 we get x = 29.
Put these value in 2.
29/8 = 5 answer.
Jordan said:
1 decade ago
First we do 56+29=85.
And 1 is quotient. Then 85 is divided by 8 then we get 5 as reminder.
And 1 is quotient. Then 85 is divided by 8 then we get 5 as reminder.
Priya Verma said:
1 decade ago
56k+29 = x.
8k+y = x.
56%8 = 7, 29%8=3 and remainder is 5.
(8+7k)+(8*3)+5.
8(7k+3)+5.
5.
8k+y = x.
56%8 = 7, 29%8=3 and remainder is 5.
(8+7k)+(8*3)+5.
8(7k+3)+5.
5.
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