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Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 93)
Numbers
93.
The largest 5 digit number exactly divisible by 91 is:
99921
99918
99981
99971
None of these
Answer: Option
Explanation:
Largest 5-digit number = 99999

 91) 99999 (1098
     91
     ---
     899
     819
     ----
      809
      728
      ---
       81
      ---
 
 Required number = (99999 - 81)
                 = 99918.
Discussion:
11 comments Page 1 of 2.
RAJATH said:   11 months ago
Actually, they have asked largest 5 digit number which is devisable by 91, if we add the difference of deviser and quotient that is 10 then it will definitely divide by 91 but it is a six-digit number.

So, if substract 99999 by 81 then the value is 99918 which is the largest 5 digit number divisible by 91.
Sree said:   2 years ago
99918 should be the correct answer.
Vishnu vardhan voleti said:   3 years ago
Largest 5 digit number always 99999.
Easy to remind 9x9=81.
So 99999-81=99918.
Deepa said:   4 years ago
Why not the remainder was subtracted from quotient and then added to the number?
Chirayu said:   4 years ago
I am not understanding this. Please, anyone explain me to get it.
Adil said:   4 years ago
You are correct, Thanks @Gooner8.
Hari said:   4 years ago
No it is not divisible by 91 @Anm.
Anm said:   6 years ago
99999 itself is divisible by 91? Then why 99999 is not that number?
Gooner8 said:   7 years ago
If 10 is added it becomes 6 dig number 99999.

= 100009.
Pranjali said:   7 years ago
Yes in fact 10 should be added in 99999. Can anyone help me out?
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