# Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 93)

93.

The largest 5 digit number exactly divisible by 91 is:

Answer: Option

Explanation:

Largest 5-digit number = 99999 91) 99999 (1098 91 --- 899 819 ---- 809 728 --- 81 --- Required number = (99999 - 81) = 99918.

Discussion:

11 comments Page 1 of 2.
RAJATH said:
11 months ago

Actually, they have asked largest 5 digit number which is devisable by 91, if we add the difference of deviser and quotient that is 10 then it will definitely divide by 91 but it is a six-digit number.

So, if substract 99999 by 81 then the value is 99918 which is the largest 5 digit number divisible by 91.

So, if substract 99999 by 81 then the value is 99918 which is the largest 5 digit number divisible by 91.

Sree said:
2 years ago

99918 should be the correct answer.

Vishnu vardhan voleti said:
3 years ago

Largest 5 digit number always 99999.

Easy to remind 9x9=81.

So 99999-81=99918.

Easy to remind 9x9=81.

So 99999-81=99918.

Deepa said:
4 years ago

Why not the remainder was subtracted from quotient and then added to the number?

Chirayu said:
4 years ago

I am not understanding this. Please, anyone explain me to get it.

Adil said:
4 years ago

You are correct, Thanks @Gooner8.

Hari said:
4 years ago

No it is not divisible by 91 @Anm.

Anm said:
6 years ago

99999 itself is divisible by 91? Then why 99999 is not that number?

Gooner8 said:
7 years ago

If 10 is added it becomes 6 dig number 99999.

= 100009.

= 100009.

Pranjali said:
7 years ago

Yes in fact 10 should be added in 99999. Can anyone help me out?

Post your comments here:

Your comments will be displayed after verification.

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers

© IndiaBIX™ Technologies