Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 8)
8.
The largest 4 digit number exactly divisible by 88 is:
9944
9768
9988
8888
None of these
Answer: Option
Explanation:
Largest 4-digit number = 9999

 88) 9999 (113
     88
     ----
     119
      88
     ----
      319
      264
      ---
       55
      ---
       
 Required number = (9999 - 55)
                 = 9944.        
Discussion:
67 comments Page 6 of 7.

Srija said:   1 decade ago
The largest no 9999/88 = 113.

And to compared to the values, /88 = 113.

9944/88 = 113.
9768/88 = 111.

9988/88 = 113.5.
8888/88 = 101.

So they equal values to show the result in 9944.

Siva said:   1 decade ago
@Balaji,

All numbers in that option are divisible by 11 and option B. And option D are also divisible both 11 and 8 then how you can say that above method is correct?

Pravallika said:   1 decade ago
I agree with @Vasanthi because give no should be divisible by both 11 and as well as 8. But we should take the rule for divisibility of 8 only not 4*2. i.e. no formed by last 3 digit no should be divisible by 8.

Karthika said:   1 decade ago
4 digits no 9999 k. But how is it 113, 88, 119, 319? Please explain sir.

Balaji said:   1 decade ago
9944.

(9+4)-(9+4)=0 or div by 11.

Last 3 digit 944 div by 8.

So it is div by 88.

Saravanan said:   1 decade ago
Another simple method.

Divide the largest number by the given number.i.e 9999/88 which is equal to 113.625

Now multiply the exact number (number before the .(dot) i.e 625 (113*88). The result would be 9944.

Also we are taking 9999 because the largest number from 01 to 1000 (the numbers given are between 01 to 1000) is 9999.

Nabarun said:   1 decade ago
The largest 4 digit number is 9999. As we have to check largest 4 digit number divisible by 88 we can exclude options b and d. 9988 is not divisible by 8. So answer is 9944.

Uday said:   1 decade ago
@sanjay.

The greatest 4 digits number i.e. 9999.

Sanjay shokeen said:   1 decade ago
I can't understand why are you take 9999.

Sitam said:   1 decade ago
To akansha it is a correct method.formula of divisible by 11 is odd place no=even place number and by 8 is the sum of first 3 digit must be divisible by 8.Here greatest number is given 9944 which fulfil the two condition above.Although others are also fulfil the conditions but they are not greatest.


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