Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 8)
8.
The largest 4 digit number exactly divisible by 88 is:
Answer: Option
Explanation:
Largest 4-digit number = 9999 88) 9999 (113 88 ---- 119 88 ---- 319 264 --- 55 --- Required number = (9999 - 55) = 9944.
Discussion:
67 comments Page 5 of 7.
Ramith said:
8 years ago
When 9999/88 = remain 55 how is that 9999/88 = 116.625?
Biswarupa rout said:
7 years ago
Why you take 9999? Please explain.
Shivraj said:
7 years ago
Because, 9999 is largest four digit number, whenever we devide it by 88 reminder remains 55, when we substract 55 from 9999 we get exact number which is divisible by 88 i.e. 9944.
Murali goud said:
7 years ago
We can write 88=11*8=11*4*2.
So the 4 digit number must be divisible by all the digits i.e 11,4,2.
But where am I confusing is the number 9988 is divisible by all the numbers i.e 11,4,2 but it is not divisible by 88.
Why? The method is wrong or write? Can anyone suggest?
So the 4 digit number must be divisible by all the digits i.e 11,4,2.
But where am I confusing is the number 9988 is divisible by all the numbers i.e 11,4,2 but it is not divisible by 88.
Why? The method is wrong or write? Can anyone suggest?
(2)
Sudeshna said:
7 years ago
@Biswarup rout.
A. 4 digit number has Th H T and One's place.
Under each place value, the minimum value we can write is 0 and the maximum value is 9. Hence, if ones, tens, hundred and Thousand all have 9, then 9999 is the largest 4 digit number.
Similarly, largest 5 digits will have 99999 so on and so forth.
The smallest 4 digit will be 1000.
Smallest 5 digit will be 10000.
A. 4 digit number has Th H T and One's place.
Under each place value, the minimum value we can write is 0 and the maximum value is 9. Hence, if ones, tens, hundred and Thousand all have 9, then 9999 is the largest 4 digit number.
Similarly, largest 5 digits will have 99999 so on and so forth.
The smallest 4 digit will be 1000.
Smallest 5 digit will be 10000.
Pankaj Namekar said:
7 years ago
9988 is the answer because;
88= (11*2*4).
9988 is completely divisible by 88.
88= (11*2*4).
9988 is completely divisible by 88.
(1)
K .srikanth said:
6 years ago
Largest 4 digit number is 9999. In the question they asked what is the largest 4digit number divisible by 88 (just we assume largest number is 9999).
Aditya said:
6 years ago
The easiest way to understand this is Euclid's division lemma.
Dividend = divisior * quatient+remainder.
So 9999 = 88 * 113 + 55..
9999-55 = 88 * 113 = 9944 = 9944.
Dividend = divisior * quatient+remainder.
So 9999 = 88 * 113 + 55..
9999-55 = 88 * 113 = 9944 = 9944.
(1)
Ruchita said:
6 years ago
Here is an easier method.
First, divide 9999 by 11(9999/11=909).
Then divide 909 by 8 (909/8 = we get 5 reminder).
But 5 is for 909.
909=5.
9999=?.
Then 9099*5/909.
We can get 55 reminder by this easy method.
First, divide 9999 by 11(9999/11=909).
Then divide 909 by 8 (909/8 = we get 5 reminder).
But 5 is for 909.
909=5.
9999=?.
Then 9099*5/909.
We can get 55 reminder by this easy method.
Aarya said:
6 years ago
Because it is the biggest 4 digit number -9999.
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