Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 8)
8.
The largest 4 digit number exactly divisible by 88 is:
Answer: Option
Explanation:
Largest 4-digit number = 9999
88) 9999 (113
88
----
119
88
----
319
264
---
55
---
Required number = (9999 - 55)
= 9944.
Discussion:
67 comments Page 2 of 7.
Nabarun said:
1 decade ago
The largest 4 digit number is 9999. As we have to check largest 4 digit number divisible by 88 we can exclude options b and d. 9988 is not divisible by 8. So answer is 9944.
Saravanan said:
1 decade ago
Another simple method.
Divide the largest number by the given number.i.e 9999/88 which is equal to 113.625
Now multiply the exact number (number before the .(dot) i.e 625 (113*88). The result would be 9944.
Also we are taking 9999 because the largest number from 01 to 1000 (the numbers given are between 01 to 1000) is 9999.
Divide the largest number by the given number.i.e 9999/88 which is equal to 113.625
Now multiply the exact number (number before the .(dot) i.e 625 (113*88). The result would be 9944.
Also we are taking 9999 because the largest number from 01 to 1000 (the numbers given are between 01 to 1000) is 9999.
Balaji said:
1 decade ago
9944.
(9+4)-(9+4)=0 or div by 11.
Last 3 digit 944 div by 8.
So it is div by 88.
(9+4)-(9+4)=0 or div by 11.
Last 3 digit 944 div by 8.
So it is div by 88.
Karthika said:
1 decade ago
4 digits no 9999 k. But how is it 113, 88, 119, 319? Please explain sir.
Pravallika said:
1 decade ago
I agree with @Vasanthi because give no should be divisible by both 11 and as well as 8. But we should take the rule for divisibility of 8 only not 4*2. i.e. no formed by last 3 digit no should be divisible by 8.
Siva said:
1 decade ago
@Balaji,
All numbers in that option are divisible by 11 and option B. And option D are also divisible both 11 and 8 then how you can say that above method is correct?
All numbers in that option are divisible by 11 and option B. And option D are also divisible both 11 and 8 then how you can say that above method is correct?
Srija said:
1 decade ago
The largest no 9999/88 = 113.
And to compared to the values, /88 = 113.
9944/88 = 113.
9768/88 = 111.
9988/88 = 113.5.
8888/88 = 101.
So they equal values to show the result in 9944.
And to compared to the values, /88 = 113.
9944/88 = 113.
9768/88 = 111.
9988/88 = 113.5.
8888/88 = 101.
So they equal values to show the result in 9944.
Prema said:
1 decade ago
88=11*8.
If 9944 is divisible by 8 and 11. It is also divisible by 88.
9944/8=1243, 9944/11=94.
So it is divisible by 88.
If 9944 is divisible by 8 and 11. It is also divisible by 88.
9944/8=1243, 9944/11=94.
So it is divisible by 88.
SAMEER said:
1 decade ago
88 - 9999 = 9911. So how it came 119. Please explain it.
Mahendra said:
10 years ago
Why can't we do it by splitting the number?
88 = 11*4*2.
Why can't we take the largest number that is divisible by 11, 4 & 2?
(This method was used to solve problem no:6).
88 = 11*4*2.
Why can't we take the largest number that is divisible by 11, 4 & 2?
(This method was used to solve problem no:6).
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers