Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 108)
108.
What is the unit digit in (4137)754?
Answer: Option
Explanation:
Unit digit in (4137)754 = Unit digit in {[(4137)4]188 x (4137)2}
=Unit digit in { 292915317923361 x 17114769 }
= (1 x 9) = 9
Discussion:
18 comments Page 1 of 2.
Ammudhanush said:
4 years ago
4137^754,
Step 1: The unit digit of the exponent 4137 is 7,
Step 2: Divide 754 by 4 (754÷4); remainder = 2,
Step 3: From step 1 &2=> 7^2 =49.
So, the unit digit of 49 is 9.
Therefore, the answer is 9.
Step 1: The unit digit of the exponent 4137 is 7,
Step 2: Divide 754 by 4 (754÷4); remainder = 2,
Step 3: From step 1 &2=> 7^2 =49.
So, the unit digit of 49 is 9.
Therefore, the answer is 9.
(8)
Krishna said:
9 years ago
The units will be like.
7^1=7.
7^2=49; unit dig=9,
For 7^3 = 343; uit dig=3.
For 7^4=___1 (unit dig =1).
Then it follows as. 7, 9, 3, 1 consecutively. Here we have cycles of 4.
Therefore, 752 can be divided from 4.
752 = 1.
753 = 7.
754 = 9; by using the cycle the answer is 9.
7^1=7.
7^2=49; unit dig=9,
For 7^3 = 343; uit dig=3.
For 7^4=___1 (unit dig =1).
Then it follows as. 7, 9, 3, 1 consecutively. Here we have cycles of 4.
Therefore, 752 can be divided from 4.
752 = 1.
753 = 7.
754 = 9; by using the cycle the answer is 9.
(4)
Reddivari radha gayathri said:
5 years ago
According to the cyclicity:
754/4 = remainder is 2.
In 4137^754 consider unit digit i.e 7^754.
replace the power with remainder i.e 7^2.
49 they asked unit digit so consider a unit digit.
Answer = 9.
754/4 = remainder is 2.
In 4137^754 consider unit digit i.e 7^754.
replace the power with remainder i.e 7^2.
49 they asked unit digit so consider a unit digit.
Answer = 9.
(3)
Aditya Dheer said:
5 years ago
The correct answer is 1.
(1)
Arvind said:
6 years ago
What will be the unit number of (3^57*6^41*7^63)?
(1)
Mohan s said:
9 years ago
@Manish Methani. How 4 To the power 4 is 2401? Just explain.
Maneesha said:
5 years ago
7^754 = ((7^4)^187)*7^6 | 7^4=81 here unit digit of 81 is 1)
= ((1)^187)*(7^4)*7^2.| 7^4=81 here unit digit of 81 is 1)
= 1*1*49.
= 1*49.
= 1*9(in 49, the number 9 is unit number)
= 9.
So is divisible by 9 so the answer is 9.
= ((1)^187)*(7^4)*7^2.| 7^4=81 here unit digit of 81 is 1)
= 1*1*49.
= 1*49.
= 1*9(in 49, the number 9 is unit number)
= 9.
So is divisible by 9 so the answer is 9.
MD AFTAB ALAM said:
6 years ago
@Manish.
4 ka 4th power =256 not 2401.
4 ka 4th power =256 not 2401.
Satpreet said:
9 years ago
If we consider (4137^2) ^377 is it right or is there compulsory to consider 4 as the power?
Avinash said:
2 decades ago
Just devide the power with 4, we get the remainder 2 and if we observe the last digits in the first four consecutive powers of 7, we get 7,9,3,1, and after that last digits will repeat again, that is every period of 4, the last digits will be repeated. So, as we got the remainder 2 when we divide the power by 4 the last digit would be 9. There is no need to expand 4173^2.
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