Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 20)
20.
The sum of first 45 natural numbers is:
1035
1280
2070
2140
Answer: Option
Explanation:

Let Sn =(1 + 2 + 3 + ... + 45). This is an A.P. in which a =1, d =1, n = 45.

Sn = n [2a + (n - 1)d] = 45 x [2 x 1 + (45 - 1) x 1] = 45 x 46 = (45 x 23)
2 2 2

= 45 x (20 + 3)

= 45 x 20 + 45 x 3

= 900 + 135

= 1035.

Shorcut Method:

Sn = n(n + 1) = 45(45 + 1) = 1035.
2 2

Discussion:
19 comments Page 1 of 2.

Md Ikramul Haque said:   7 years ago
4+5=9.
And 1035=1+0+3+5=9.
Answer is A.
(13)

Nivetha said:   5 years ago
The formula for an average of natural numbers is n+1/2,
45+1/2 = 23,
Therefore, 45 natural numbers *23 = 1035.
(9)

Prasannakumar said:   6 years ago
If the difference between the same throughout the series at that time only we use:

1) Sum of 'N' natural numbers(Sn) = n(n+1)/2.
(Or)
2) Sn = n/2 [2a+(n-1)d]

Here, d = difference.
n = Total numbers.
a = 1st number.

Actually AP series is a,a+d,a+2d,a+3d+....+a+(n-1)d.
That's why we take a=1.

If we take 'x' in place of 'a' in above series, the formula will Become,

Sn = n/2 [2x+(n-1)d].
(2)

Rohit Singla said:   1 decade ago
Middle no.of 45 is 23.
So its average is also 23.

23*45 = 1035.
(1)

Bhartari Shinde said:   6 years ago
n(n+1)/2 = 45(45+1)/2 = 2070/2 = 1035.
(1)

Ninjahari said:   6 years ago
n(n+1)/2 is applicable. Am I right?
(1)

Manali said:   9 years ago
Simplest way to multiply the given number with its consecutive number and then divide by 2.
i.e (45 * 46)/2 = 1035.
(1)

Tohid said:   8 years ago
n(n + 1)÷2 = 45(45 + 1)÷2 = 1035.
(1)

KrishanuS said:   10 months ago
In 45 there are odd numbers of odd numbers. 23 odd numbers so the answer of sum gonna be another odd number.

Hence 1035 is the answer (As there is only one odd number). If there is more than one apply n* (n+1) /2.

Bill said:   1 decade ago
Help me to find even more easy way.


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