Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 18)
18.
Which one of the following numbers is exactly divisible by 11?
Answer: Option
Explanation:
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
Discussion:
46 comments Page 3 of 5.
Maya said:
1 decade ago
It is the principle for dividing any No. by 11.
If the difference between odd & even places No. comes 0 or 11 or multiple of 11 i.e. 22, 99, 121 etc. Then the whole No. will be divided by 11.
For example we also have principle for dividing any No. by 2. i.e.the unit place No. is divided by 2 that means the whole No. is divided by 2.
If the difference between odd & even places No. comes 0 or 11 or multiple of 11 i.e. 22, 99, 121 etc. Then the whole No. will be divided by 11.
For example we also have principle for dividing any No. by 2. i.e.the unit place No. is divided by 2 that means the whole No. is divided by 2.
Debashish Mohapatra said:
1 decade ago
There is another method as well. In the option A, B, C. If you will add all the digits of the given number the result will not be divisible by 11. But if you will add the digits of the number given in option D.
i.e - 415624=4+1+5+6+2+4=22 which is divisible with 11.
This formula is also applicable for any number.
i.e - 415624=4+1+5+6+2+4=22 which is divisible with 11.
This formula is also applicable for any number.
(1)
Sindhu said:
1 decade ago
2+3+5+6+4+1=21 it is not divisible by 11.
2+4+5+6+4+2=23 it is not divisible by 11.
3+1+5+6+2+4=21 it is not divisible by 11.
4+1+5+6+2+4=22 it is divisible by 11.
Answer:415624.
2+4+5+6+4+2=23 it is not divisible by 11.
3+1+5+6+2+4=21 it is not divisible by 11.
4+1+5+6+2+4=22 it is divisible by 11.
Answer:415624.
Masood tahir said:
1 decade ago
@abhi.
I think Arjun is right as;
209/11= 19 which is completely devise-able by 11 by leaving no remainder, with short cut method for aptitude as; 2+0+9=11 which is also completely divided by 11.
I think Arjun is right as;
209/11= 19 which is completely devise-able by 11 by leaving no remainder, with short cut method for aptitude as; 2+0+9=11 which is also completely divided by 11.
Vidyadhar said:
1 decade ago
Divisibility rule:
Form the alternating sum of the digits.
415624 = 4-1+5-6+2-4
= 4+4-4-4
= 8-8
= 0
0 divisible by 11.
So Answer is 415624.
Form the alternating sum of the digits.
415624 = 4-1+5-6+2-4
= 4+4-4-4
= 8-8
= 0
0 divisible by 11.
So Answer is 415624.
Bhaskar said:
1 decade ago
If you take 209/11.
Then your logic.
Because 2+10+9=21,
21 is not divisible.
Then your logic.
Because 2+10+9=21,
21 is not divisible.
Reena said:
1 decade ago
2+3+5+6+4+1 = 21/11.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible by 11.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible by 11.
Nagasri said:
1 decade ago
Alternative numbers sum and take their difference. if the difference is 0 or divisible by 11.
Then that numbers are divisible by 11. that means,
eg:415624.
4+5+2 = 11.
1+6+4 = 11.
then difference = 11-11 = 0.
divisible by 11.
If we take any number. We got answer.
Then that numbers are divisible by 11. that means,
eg:415624.
4+5+2 = 11.
1+6+4 = 11.
then difference = 11-11 = 0.
divisible by 11.
If we take any number. We got answer.
Amit Chutani said:
1 decade ago
2+3+5+6+4+1 = 21/11.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible.
2+4+5+6+4+2 = 25/11.
3+1+5+6+2+4 = 21/11.
4+1+5+6+2+4 = 22/11 = 2 it is divisible.
Sachin said:
1 decade ago
Sum of digits = (4 + 1 + 5 + 6 + 2 + 4) = 22, which must be divisible by 11.
So answer is 415624.
So answer is 415624.
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