Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 51)
51.
476 ** 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively:
Answer: Option
Explanation:
Let the given number be 476 xy 0.
Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.
And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.
x - y - 3 = 0 
y = x - 3
(17 + x + y) = (17 + x + x - 3) = (2x + 14)
x= 2 or x = 8.
x = 8 and y = 5.
Discussion:
37 comments Page 4 of 4.
Sumit jain said:
1 decade ago
The 1st option is also suiting well in the sum. Then the numbers ll be divisible by both 11 and 3 ?
Priyanka said:
10 years ago
Why not there answer as 7, 4?
Animesh said:
10 years ago
@Akash.
You see that in question it's written that the number, 476**0 is divisible by 3 then the sum of numbers like, (4+7+6+x(x mean *) + y(y mean *)+0) is also be divisible by 3. It's a rule.
You see that in question it's written that the number, 476**0 is divisible by 3 then the sum of numbers like, (4+7+6+x(x mean *) + y(y mean *)+0) is also be divisible by 3. It's a rule.
Dhanashri said:
9 years ago
Please explain this step, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.
Prateek said:
9 years ago
Thank you so much @Tanya Mazumdar.
Poonam said:
9 years ago
How did y = 5 come?
Parampreet Singh said:
1 decade ago
What about x=5 and y=2 as answer?
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