Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 51)
51.
476 ** 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively:
Answer: Option
Explanation:
Let the given number be 476 xy 0.
Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.
And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.
x - y - 3 = 0 
y = x - 3
(17 + x + y) = (17 + x + x - 3) = (2x + 14)
x= 2 or x = 8.
x = 8 and y = 5.
Discussion:
37 comments Page 2 of 4.
Jashim uddin said:
7 years ago
Thanks @Tanya.
Rinkal said:
8 years ago
Thanks @Tanya Mazumdar.
Pritam Bose said:
8 years ago
Thank you @Tanya Mazumdar.
Shahid ali said:
8 years ago
Thank you @Tanya.
Vishnu Priya said:
9 years ago
Please can anyone explain from (0 + x + 7) - (y + 6 + 4) =x - y - 3. Must be either 0 or 11?
Padman said:
9 years ago
5 and 2 are not there in the answers given. Hence 8 and 5 selected.
Rahul said:
9 years ago
By solving through divisibility method we can aslo get value X = 5 and Y = 2. Is it correct?
Harikrishna said:
9 years ago
(0 + x + 7) - (y + 6 + 4) = (x - y -3) .
Please tell me how can we get second line condition please explain in detail, please.
Please tell me how can we get second line condition please explain in detail, please.
Poonam said:
9 years ago
How did y = 5 come?
Mayank said:
9 years ago
I can't understand please explain me from first step to last step.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers