Aptitude - Numbers - Discussion

547804 is divisible by 2,3,4 then why its not divisible by 24.. can u explain?

5+4+7+8+0+4=28 is not divisible by 3, it can't by 24 also

Hello syama..
547804 is not divisible by 3..
divisible by means "remainder should be zero"

Hell friends, I did not get why your dividing total number with 8 and sum of total numbers with 3 and on what basis your selecting 8 for dividing total number and on what basis your selecting 3 for dividing sum of total number.

Can anybody explain me?

Hi Reddy :

They took 8 and 3 because 3*8=24 any number divisible by 24 should be divisible by its divisors

You can also take 4*6

537804 is divisible by 2, 3, 4.

So 537804 is also divisible by 24 na?

If 537804 /24, the remainder will be 0. So the answer will be c and d.

Can anyone clear my doubt?

How can you take only last 3 digits of a number ?

@Rajak

Because there are some short methods to find out weather the number is divided by 2,3,4,5,6,7,8,9,10,11.

For example:- if the last digit of any number is 0,2,4,6,8 then it is fully divided by 2 for example 63470.

If the sum of all the digits in number is divided by 3 then the number will be divide by the 3 for example = (3 + 1 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 3 so the digit 3125736 will be fully divided by 3.

For 8 it is like if the last three digits are divided by eight then only it can be fully divided by 8 for example above... and so on.

537804 is divisible by 2, 3, 4.

So 537804 is also divisible by 24 na?

If 537804 /24, the remainder will be 0. So the answer will be c and d.

---plz explain why c option cant be the answer

@Bindhu.

4 and 6 are not co-prime, because they share the common factor 2; and gcd(4,6)=2.