Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 65)
65.
If the number 42573 * is exactly divisible by 72, then the minimum value of * is:
Answer: Option
Explanation:
72 = 9 x8, where 9 and 8 are co-prime.
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
Required value of * is 6.
Discussion:
17 comments Page 1 of 2.
Kinnaboy said:
3 years ago
Standard form of 72 = 3^2 * 2^3.
i.e. 72 = 9*8.
If a number is divisible by a number a and a number b, and both a and b are co-primes i.e. they have no common factor other than 1. then the number is divisible by a*b. e.g. if 120 is divisible by 2 and 3 therefore 120 is divisible by 2*3.
Also 120 is divisible by 8 and 2, but it won't be divisible by 8 * 2 because 8 and 2 are not co-primes.
In the above case 9 and 8 are coprime therefore check for divisibility by 8 and 9.
For divisibility by 8 : the last digit must be even and the last 3 digits must be divisible by 8.
for divisibility by 9: sum of all digit must be divisible by 9.
Therefore check 4+2+5+7+3+x such that x is even first, then the sum is divisible by 9 and lastly, last 3 digits are divisible by 8.
You won't have to do the last step though since the only even number making the sum of digits divisible by 9 is 6: 4+2+5+7+3+6 = 27.
Hence 6 is the answer
i.e. 72 = 9*8.
If a number is divisible by a number a and a number b, and both a and b are co-primes i.e. they have no common factor other than 1. then the number is divisible by a*b. e.g. if 120 is divisible by 2 and 3 therefore 120 is divisible by 2*3.
Also 120 is divisible by 8 and 2, but it won't be divisible by 8 * 2 because 8 and 2 are not co-primes.
In the above case 9 and 8 are coprime therefore check for divisibility by 8 and 9.
For divisibility by 8 : the last digit must be even and the last 3 digits must be divisible by 8.
for divisibility by 9: sum of all digit must be divisible by 9.
Therefore check 4+2+5+7+3+x such that x is even first, then the sum is divisible by 9 and lastly, last 3 digits are divisible by 8.
You won't have to do the last step though since the only even number making the sum of digits divisible by 9 is 6: 4+2+5+7+3+6 = 27.
Hence 6 is the answer
(2)
M. usha said:
4 years ago
I got confused, Could anyone please explain clearly?
(3)
Sathya said:
5 years ago
How 73x will came in solving x = 6? Please explain this step.
(1)
Nandini said:
6 years ago
How 6 will be the answer? please explain.
Arun Prasanth v said:
7 years ago
42573* ÷ 72,
First we do,
72 = 9*8.
Then,
The sum of num 42573* is divisible are not divisible by 9,
4+2+5+7+3+x = 21+x,
Now see we take 6 to add and then the number is divisible,
21+6= 27 now it is divided so the x =6.
First we do,
72 = 9*8.
Then,
The sum of num 42573* is divisible are not divisible by 9,
4+2+5+7+3+x = 21+x,
Now see we take 6 to add and then the number is divisible,
21+6= 27 now it is divided so the x =6.
(2)
Vinod said:
7 years ago
Why should a take 6 and 73x?
Pankaj Verma 9041939259 said:
8 years ago
73x is divisible by 8 is, x = ?
First divide 73/8.
8x9 = 72 remainder 1.
73 1 X we need 6(1 is remainder while dividing 73 with 8 after remainder we have to put the value of X).
1X/8 as we know 16/8 so X is 6.
First divide 73/8.
8x9 = 72 remainder 1.
73 1 X we need 6(1 is remainder while dividing 73 with 8 after remainder we have to put the value of X).
1X/8 as we know 16/8 so X is 6.
Shree said:
8 years ago
425736/72 =6.
Atul said:
9 years ago
72 is known that is divisible by 3.
And any number, multiplied by 72 will be even.
And, 4 + 2 + 5 + 7 + 3 = 21, which is divisible by 3 "known".
We need to find an option from rest of the options which is even and divided by 3.
And any number, multiplied by 72 will be even.
And, 4 + 2 + 5 + 7 + 3 = 21, which is divisible by 3 "known".
We need to find an option from rest of the options which is even and divided by 3.
Saravanan said:
10 years ago
Easy method:
72 is always divisible by(9*8),
Note: always take the minimum value here min value is : 8.
Now take the last 3 digits and place 8 in place of 'x'.
Then use all the given options,
Ex: 73* => 738/4 it will not give. So by the way we can get only by using 6.
i.e: 738/6 = 123.
Hence the answer: 6.
Thank you.
72 is always divisible by(9*8),
Note: always take the minimum value here min value is : 8.
Now take the last 3 digits and place 8 in place of 'x'.
Then use all the given options,
Ex: 73* => 738/4 it will not give. So by the way we can get only by using 6.
i.e: 738/6 = 123.
Hence the answer: 6.
Thank you.
(1)
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