Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 24)
24.
If the number 481 * 673 is completely divisible by 9, then the smallest whole number in place of * will be:
Answer: Option
Explanation:
Sum of digits = (4 + 8 + 1 + x + 6 + 7 + 3) = (29 + x), which must be divisible by 9.
x = 7.
Discussion:
16 comments Page 2 of 2.
Kranti said:
1 decade ago
Hello muskan. If he won't ask us to take smallest whole no. then we may also take x=15. Which is also correct one?
Sanjeev varma said:
1 decade ago
Here the quest smallest hole no. which is divisible by 9.
A small technique,
If the sum of all no. equal to 9 then it is divisible by 9.
Ex:
15462.
1+5+4+6+2=18=> 1+8 =9 so it is divisible by 9.
Another case,
15460.
1+5+4+6+0=16=>1+6=7 if we add 2 to it then it will divisible by 9.
Same as to this question.
A small technique,
If the sum of all no. equal to 9 then it is divisible by 9.
Ex:
15462.
1+5+4+6+2=18=> 1+8 =9 so it is divisible by 9.
Another case,
15460.
1+5+4+6+0=16=>1+6=7 if we add 2 to it then it will divisible by 9.
Same as to this question.
Vikas mahant said:
1 decade ago
As you seen sum of digit is (29+x). So we have to feed the value of x which make digit divisible by 9.
29+x.
If we put x = 7.
Then 29+7 = 36.
Divisible by 9.
If we put 2 in place of 7.
Then (29+2) = 31.
Not divisible by 9.
29+x.
If we put x = 7.
Then 29+7 = 36.
Divisible by 9.
If we put 2 in place of 7.
Then (29+2) = 31.
Not divisible by 9.
Sunil said:
9 years ago
Please give any logical trick to find the answer.
Jagannath said:
7 years ago
I think the is answers is B) 5.
Vijaybaranwal said:
6 years ago
Why? tell me.
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