Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 94)
94.
| 768 x 768 x 768 + 232 x 232 x 232 | = ? |
| 768 x 768 - 768 x 232 + 232 x 232 |
Answer: Option
Explanation:
| Given Exp. = | (a3 + b3) | = (a + b) = (768 + 232) = 1000 |
| (a2 - ab + b2) |
Discussion:
5 comments Page 1 of 1.
Nicholas Muhumuza said:
3 weeks ago
I still don't get it.
MOUNIKA said:
3 years ago
Let a=768 and b= 232.
Then, the given expression.
768 * 768 * 768 + 232 * 232 * 232/768 * 768 - 768 * 232 + 232 * 232.
Can be written as;
(a3+b3)/(a2+b2-ab) =
As we know, (a3+b3)=(a+b)(a2+b2-ab);
so by this;
(a+b)(a2+b2-ab)/(a2+b2-ab).
Deleting (a2+b2-ab) from both the sides;
we remain with a+b.
768+232 = 1000.
So, A is the correct answer.
Then, the given expression.
768 * 768 * 768 + 232 * 232 * 232/768 * 768 - 768 * 232 + 232 * 232.
Can be written as;
(a3+b3)/(a2+b2-ab) =
As we know, (a3+b3)=(a+b)(a2+b2-ab);
so by this;
(a+b)(a2+b2-ab)/(a2+b2-ab).
Deleting (a2+b2-ab) from both the sides;
we remain with a+b.
768+232 = 1000.
So, A is the correct answer.
(1)
Xyz said:
8 years ago
Here the formula is;
(a3 + b3) = (a + b)(a2 - ab + b2)
So, (a3 + b3)/(a2 - ab + b2)=(a+b)
In the given question a is taken as 768 and b as 232.
Therefore,(a+b)=768+232=1000.
(a3 + b3) = (a + b)(a2 - ab + b2)
So, (a3 + b3)/(a2 - ab + b2)=(a+b)
In the given question a is taken as 768 and b as 232.
Therefore,(a+b)=768+232=1000.
Rajalakshmi said:
8 years ago
I can't understand it, pleas help me.
(1)
Sumon said:
8 years ago
I can't understand please help me by explaining the answer.
(1)
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