Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 2)
2.
(112 x 54) = ?
67000
70000
76500
77200
Answer: Option
Explanation:
(112 x 54) = 112 x 10 4 = 112 x 104 = 1120000 = 70000
2 24 16
Discussion:
126 comments Page 8 of 13.

Vinitha said:   1 decade ago
5*5*5*5 = 625.

112*625 = 70000.

It is the simple step.

Umar kce said:   1 decade ago
Our author says easiest way.

Ex: Any no which is multiply by multiples of 5 we can follow these method.

= 187*5= 1870/2 = 935.

i.e, 5^1 = 5. So one zero.

If 125 means 5^3 = 125, so 000 to be added.

How many zero to be added in numerator that much of 2 to be added in denominator?

If 625 means in 1870000/2*2*2*2.

Aniruddha Wagh said:   1 decade ago
2x5 gives 0 at unit place.

2^2x5^2 gives two zeros at last of number i.e. at unit and tens place.

Similarly for higher power gives respective zeroes at end. Now you can easily solved it. No need for me to solve.

Sindhu said:   1 decade ago
This is simple method.

Yekambaram said:   1 decade ago
I want best method.

Shefali said:   1 decade ago
We can simply check the number of zeros by determining the number of 5's.

Here, number of 5 = 4.

So, the answer will must have 4 zeros in last! So, here the answer will be 70000!

Siva said:   1 decade ago
We can use simple method:

5^4 = 5*5*5*5 = 625.

Then this to multiply with 112.

You can easily get answer 112*625 = 70000.

Bhupendra said:   1 decade ago
It's so simple.

= 16x7x5^4.

= 7x (2^4x5^4).

= 7x (2x5) ^4 = 70000.

Shakila said:   1 decade ago
Using the calculator we got the easy calculation.

(112*5*5*5*5) = 70000.

Manohar said:   1 decade ago
@Shefali you nailed it. Just count the power of 5, and that many zeros have to be in answer.


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