Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 2)
2.
(112 x 54) = ?
Answer: Option
Explanation:
| (112 x 54) = 112 x |  |
10 |  |
4 | = | 112 x 104 | = | 1120000 | = 70000 |
| 2 | 24 | 16 |
Discussion:
124 comments Page 1 of 13.
Ramya said:
1 decade ago
I want any more explanation.
Tejas said:
1 decade ago
This is the best method.
Ramu said:
1 decade ago
I want easy and simple method.
Santhi said:
1 decade ago
(4*4*7)*25*25
(4*25)*(4*25)*7=70000
(4*25)*(4*25)*7=70000
Tamilarasi said:
1 decade ago
How to put 10/2.......
If you write 10/2 means this ans is 5
In these sums easy way to get the ans.
eg:25 means 50/2.
112*10*10*10*10
_______________ = 70,000
2*2*2*2
If you write 10/2 means this ans is 5
In these sums easy way to get the ans.
eg:25 means 50/2.
112*10*10*10*10
_______________ = 70,000
2*2*2*2
Arun raj said:
1 decade ago
112*5*5*5*5 = 70000
simple:-)
simple:-)
Suresh kumar said:
1 decade ago
I want more explanations.
RAVI SHASTRI said:
1 decade ago
SANTHI YOUR METHOD IS BEST
Ananya said:
1 decade ago
112 x 5^4 = (2^4 * 7) * 5^4
= 2^4 * 5^4 * 7
= (2*5)^4 * 7
= 10^4 * 7
= 70000
= 2^4 * 5^4 * 7
= (2*5)^4 * 7
= 10^4 * 7
= 70000
(1)
Phani Gorantla said:
1 decade ago
Here we can apply 2*5 as a zero technique
for ex 2*2^2*5^2
Now ans is 200(i.e in this pbm two 2's two 5 combination is there thats why i just put two zeros after 2.
Now the given pbm i converted into 2's and 5's combination
(112)*5^4
(7*2^4)*5^4
i.e 7*(2^4*5^4)ans is 70000(4 zeros added after 7 because four 2's and 5's combinations are there)
for ex 2*2^2*5^2
Now ans is 200(i.e in this pbm two 2's two 5 combination is there thats why i just put two zeros after 2.
Now the given pbm i converted into 2's and 5's combination
(112)*5^4
(7*2^4)*5^4
i.e 7*(2^4*5^4)ans is 70000(4 zeros added after 7 because four 2's and 5's combinations are there)
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