Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 2)
2.
(112 x 54) = ?
Answer: Option
Explanation:
| (112 x 54) = 112 x |  |
10 |  |
4 | = | 112 x 104 | = | 1120000 | = 70000 |
| 2 | 24 | 16 |
Discussion:
125 comments Page 8 of 13.
Aaisha said:
10 years ago
Simply by calculator,
112*5^4=70000.
112*5^4=70000.
RAVI KANT said:
10 years ago
Multiplication of a number by 5^n: Put n zeros to the right of the multiplicand and divide the number so formed by 2^n.
So (112 x 5^4) = 1120000/2^4 = 1120000/16 = 70000.
Note: It is only apply for 5^n.
Thank you.
So (112 x 5^4) = 1120000/2^4 = 1120000/16 = 70000.
Note: It is only apply for 5^n.
Thank you.
(1)
Manohar said:
10 years ago
@Shefali you nailed it. Just count the power of 5, and that many zeros have to be in answer.
Shakila said:
10 years ago
Using the calculator we got the easy calculation.
(112*5*5*5*5) = 70000.
(112*5*5*5*5) = 70000.
Bhupendra said:
10 years ago
It's so simple.
= 16x7x5^4.
= 7x (2^4x5^4).
= 7x (2x5) ^4 = 70000.
= 16x7x5^4.
= 7x (2^4x5^4).
= 7x (2x5) ^4 = 70000.
Shefali said:
10 years ago
We can simply check the number of zeros by determining the number of 5's.
Here, number of 5 = 4.
So, the answer will must have 4 zeros in last! So, here the answer will be 70000!
Here, number of 5 = 4.
So, the answer will must have 4 zeros in last! So, here the answer will be 70000!
Siva said:
10 years ago
We can use simple method:
5^4 = 5*5*5*5 = 625.
Then this to multiply with 112.
You can easily get answer 112*625 = 70000.
5^4 = 5*5*5*5 = 625.
Then this to multiply with 112.
You can easily get answer 112*625 = 70000.
Yekambaram said:
10 years ago
I want best method.
Sindhu said:
10 years ago
This is simple method.
Aniruddha Wagh said:
1 decade ago
2x5 gives 0 at unit place.
2^2x5^2 gives two zeros at last of number i.e. at unit and tens place.
Similarly for higher power gives respective zeroes at end. Now you can easily solved it. No need for me to solve.
2^2x5^2 gives two zeros at last of number i.e. at unit and tens place.
Similarly for higher power gives respective zeroes at end. Now you can easily solved it. No need for me to solve.
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