Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 138)
138.
{(476 + 424)2 - 4 x 476 x 424} = ?
Answer: Option
Explanation:
| Given Exp. | = [(a + b)2 - 4ab], where a = 476 and b = 424 |
| = [(476 + 424)2 - 4 x 476 x 424] | |
| = [(900)2 - 807296] | |
| = 810000 - 807296 | |
| = 2704. |
Discussion:
10 comments Page 1 of 1.
G Ajay Kumar said:
2 years ago
(a + b)^2 - 4ab = a^2 + b^2 + 2ab -4ab.
= a^2 + b^2 - 2ab,
= (a - b)^2.
therefore, the above equation can be written as,
= {(476 + 424)^2 - 4 x 476 x 424}.
= ( 476^2 + 424^2 - 2 x 476 x 424),
= (476 - 424)^2,
= 52^2,
= 2704.
= a^2 + b^2 - 2ab,
= (a - b)^2.
therefore, the above equation can be written as,
= {(476 + 424)^2 - 4 x 476 x 424}.
= ( 476^2 + 424^2 - 2 x 476 x 424),
= (476 - 424)^2,
= 52^2,
= 2704.
(8)
Krishna said:
7 years ago
4ab=(a+b)^2-(a-b)^2.
Thus (a+b) ^2-4ab=(a-b)^2..
a-b=476-424=52.
52^2=2704 =>answer.
Thus (a+b) ^2-4ab=(a-b)^2..
a-b=476-424=52.
52^2=2704 =>answer.
(5)
Arif said:
1 decade ago
[(a+b)^2-4ab]=a^2+b^2+2ab-4ab
=(a-b)^2
=(476-424)^2
=52^2
=2704
=(a-b)^2
=(476-424)^2
=52^2
=2704
(3)
Bindu said:
9 years ago
This is in the form of (a + b)^2 - 4ab.
So, (a^2 + b^2 + 2ab - 4ab).
= a^2 + b^2 - 2ab.
= (a - b)^2.
So, a = 476, b = 424 by substituting the value we get the answer.
= 2704.
So, (a^2 + b^2 + 2ab - 4ab).
= a^2 + b^2 - 2ab.
= (a - b)^2.
So, a = 476, b = 424 by substituting the value we get the answer.
= 2704.
(3)
Suraj said:
7 years ago
Sum of two numbers is twice their difference. If one of the number is 10then the other no is?
Please, anyone, answer this.
Please, anyone, answer this.
(2)
Shahid said:
1 decade ago
[(a + b)2 - 4ab]=[(a-b)^2]
From the above we have a=476 ,b=424
so Result is (476-424)^2
=52^2=2704
From the above we have a=476 ,b=424
so Result is (476-424)^2
=52^2=2704
(1)
Pritam said:
8 years ago
Nice and easy method @Bindu.
(1)
Swar said:
7 years ago
@Suraj.
Let two numbers be considered as x and y
As per question ,x+y=2(x-y) ,
Given one numbers as 10,
10+y=2(10-y),
10+y=20-2y,
2y+y=20-10,
3y=10,
Y=10/3.
Correct me, if I am wrong.
Let two numbers be considered as x and y
As per question ,x+y=2(x-y) ,
Given one numbers as 10,
10+y=2(10-y),
10+y=20-2y,
2y+y=20-10,
3y=10,
Y=10/3.
Correct me, if I am wrong.
(1)
Siva said:
1 decade ago
[(a+b)^2-4ab] = a^2+b^2+2ab-4ab.
= (a-b)^2.
= (476-424)^2.
= 52^2.
= 2704.
= (a-b)^2.
= (476-424)^2.
= 52^2.
= 2704.
Ipsita said:
10 years ago
But as we know:
(a-b)^2 = a^2-2ab+b^2.
(a-b)^2 = a^2-2ab+b^2.
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