Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 15)
15.
72519 x 9999 = ?
Answer: Option
Explanation:
| 72519 x 9999 | = 72519 x (10000 - 1) |
| = 72519 x 10000 - 72519 x 1 | |
| = 725190000 - 72519 | |
| = 725117481. |
Discussion:
17 comments Page 1 of 2.
Aashu said:
5 years ago
7 + 2 + 5 + 1 + 9 = 24 again 2 + 4=6
9 + 9 + 9 + 9 = 36 again 3 + 6 =9
Given =72519 * 9999 = 9 * 6 = 54 sum of 5 + 4= 9
Now find the sum of the digits in the given option
A)7 + 2 + 5 + 1 + 1 + 7 + 4 + 8 + 1 = 9,
Similarly for
B)4
C)5
D)8
So, option A is the correct answer. Hope my answer is useful.
9 + 9 + 9 + 9 = 36 again 3 + 6 =9
Given =72519 * 9999 = 9 * 6 = 54 sum of 5 + 4= 9
Now find the sum of the digits in the given option
A)7 + 2 + 5 + 1 + 1 + 7 + 4 + 8 + 1 = 9,
Similarly for
B)4
C)5
D)8
So, option A is the correct answer. Hope my answer is useful.
(23)
Anurag said:
4 years ago
@All.
The best short trick to multiply any digit with 99,999,999,99999999,..
Example;
33 * 99 = 33 -1 || 9-3 || 10-3 => 3267.
237 * 999 = 237-1 || 9-2 || 9-3 || 10 - 7 (10 - last digit) => 236763.
The best short trick to multiply any digit with 99,999,999,99999999,..
Example;
33 * 99 = 33 -1 || 9-3 || 10-3 => 3267.
237 * 999 = 237-1 || 9-2 || 9-3 || 10 - 7 (10 - last digit) => 236763.
(3)
Roshan said:
10 years ago
I think it's 72446481.
Is it correct?
Is it correct?
(3)
Manoj said:
5 years ago
From where do we get 5x?
(2)
Abid said:
8 months ago
It is much easier if we find the sum of the digits. Only opt A's Digits' sum is divisible by 9.
So, that's the answer.
So, that's the answer.
(1)
Sree said:
1 decade ago
It is very simple method 72519 * 9999.
72519 * 9000 = 652671000,
72519 * 900 = 65267100,
72519 * 90 = 6526710,
72519 * 9 = 652671.
Then 652671000 + 65267100 + 6526710 + 652671 = 725117481.
72519 * 9000 = 652671000,
72519 * 900 = 65267100,
72519 * 90 = 6526710,
72519 * 9 = 652671.
Then 652671000 + 65267100 + 6526710 + 652671 = 725117481.
(1)
Vamsi aripaka said:
8 years ago
Thank for explaining the solution.
(1)
Mustafa said:
7 years ago
This trick always works if m * n when the numbers in m > n and n = any number of 9's sequence.
1) Count number of 9's in n.
2) Add those many 0's in the m number.
3) Subtract the original number.
eg> 72519 * 9999.
m=5 , n = 4 thus m>n.
721590000-72519= 725117481.
1) Count number of 9's in n.
2) Add those many 0's in the m number.
3) Subtract the original number.
eg> 72519 * 9999.
m=5 , n = 4 thus m>n.
721590000-72519= 725117481.
(1)
Mustafa said:
7 years ago
It works if m * n when the numbers in m > n and n = any number of 9's sequence.
1) count number of 9's in n.
2) add those many 0's in the m number.
3) subtract the original number.
eg> 72519 * 9999.
m=5 , n = 4 thus m>n.
721590000-72519= 725117481.
1) count number of 9's in n.
2) add those many 0's in the m number.
3) subtract the original number.
eg> 72519 * 9999.
m=5 , n = 4 thus m>n.
721590000-72519= 725117481.
(1)
Nishanth said:
3 weeks ago
USE BODMAS METHOD:
(12)^3 × 6^4 ÷ 432 = x.
1732 × 1296 ÷ 432 = x.
1732 × 16 = 27712.
X = 27712.
(12)^3 × 6^4 ÷ 432 = x.
1732 × 1296 ÷ 432 = x.
1732 × 16 = 27712.
X = 27712.
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