Aptitude - Numbers - Discussion

Super trick @Suba.

If we know the concept of cyclicity we can find the last digits in each number given.

In 12^3 the end digit will be 8. In 6^4 end digit will be 6 and in 432 it's 2. So it will be 8*6/2 which will be 24. Thus end digit in the final answer should be 4.

Now there are two options with end digits as 4. So the next step is to find the digital sum. In the question the digital sum will be 1 + 2 + 6+ 4 + 3 + 2 = 18 further 1 + 8 is 9. So in whichever option ending with 4 along with digital sum as 9 is the right option. In option 1 the digital sum is 5 + 1 + 8 + 4 which is 18 and further it can be 1+8 that is 9. So the option with end digit 4 and digital sum 9 is option A.

Thank you @Kiran Kumar.

Here, what is the question?

I can't understand the question itself. Please explain me, anyone?

Digital sum is not working to all other numbers @Kiran Kumar.

I can't understand.

How is to (12^2) * (6^2) = 72^2?

Please, somebody tell me How can you know that 432 = 12 x 6^2?

How can you evaluate the factors of 432= 12 * 6^2?

Thank you @Kiran Kumar.

Why don't we use BODMAS rule?