### Discussion :: Numbers - General Questions (Q.No.14)

Prash said: (Dec 8, 2010) | |

Can't we do it with BODMAS method? |

Suba said: (Dec 25, 2011) | |

Simple method 12x12x12x6x6x6x6/432=5184 this is the answer easy method |

Hari said: (Jun 25, 2012) | |

How can you know that 432 = 12*6^2 ? |

Majid said: (Dec 7, 2012) | |

more simple 12*12*12*6*6*6*6/12*6*6=5184 |

Sachin M Nayaka said: (Dec 24, 2012) | |

12*12*12*6*6*6*6/432 3*12*12*6*6*6*6/108 3*12*12*6*6*6/18 3*12*12*6*6/3 12*12*6*6=5184 |

Preethi Santhosh said: (Oct 24, 2014) | |

12*12*12*6*6*6*6/6*6*6*2 This is also one of the simplest method. |

Ammu said: (Jun 26, 2015) | |

12x12x12x6x6x6x6/6x6x3x2x2 = 5184. |

Jugal said: (Mar 22, 2016) | |

How can you know that 432=12x6^2? |

Shivsainik said: (Jul 18, 2016) | |

1728/432 * 6^4 = 4 * 1296 = 5184. |

Sree said: (Jul 20, 2016) | |

12 * 12 * 12 * 6 * 6 * 6 * 6/2 * 2 * 2 * 2 * 3 * 3 * 3. Then 12 * 12 * 12 * 3 = 5184. It is very simple. |

Raghavi said: (Jul 30, 2016) | |

Super trick @Suba. |

Kiran Kumar said: (Aug 5, 2016) | |

If we know the concept of cyclicity we can find the last digits in each number given. In 12^3 the end digit will be 8. In 6^4 end digit will be 6 and in 432 it's 2. So it will be 8*6/2 which will be 24. Thus end digit in the final answer should be 4. Now there are two options with end digits as 4. So the next step is to find the digital sum. In the question the digital sum will be 1 + 2 + 6+ 4 + 3 + 2 = 18 further 1 + 8 is 9. So in whichever option ending with 4 along with digital sum as 9 is the right option. In option 1 the digital sum is 5 + 1 + 8 + 4 which is 18 and further it can be 1+8 that is 9. So the option with end digit 4 and digital sum 9 is option A. |

Palani said: (Aug 15, 2016) | |

Thank you @Kiran Kumar. |

Ashok said: (Aug 21, 2016) | |

Here, what is the question? I can't understand the question itself. Please explain me, anyone? |

Hunanda said: (Aug 26, 2016) | |

Digital sum is not working to all other numbers @Kiran Kumar. |

Arunkumar said: (Dec 23, 2016) | |

I can't understand. How is to (12^2) * (6^2) = 72^2? |

Stephy George said: (Jan 5, 2017) | |

Please, somebody tell me How can you know that 432 = 12 x 6^2? |

Sharthak said: (Jan 10, 2017) | |

How can you evaluate the factors of 432= 12 * 6^2? |

Niranjani said: (Feb 6, 2017) | |

Thank you @Kiran Kumar. |

Krishna said: (Feb 22, 2017) | |

Why don't we use BODMAS rule? |

Mehak said: (Jun 3, 2017) | |

12 * 12 * 12 * 6 * 6 * 6 * 6/27 * 2 * 2 * 2 * 2, = 5184. |

Preet said: (Jun 23, 2017) | |

Please explain answer. I couldn't understand so please tell me the answer. |

Puja said: (Jul 13, 2017) | |

Thank you so much @Kiran. |

Mvs said: (Jul 25, 2017) | |

@Kiran Kumar. Your method is very helpful to find the right answer quickly. Thanks. |

Anushka said: (Aug 2, 2017) | |

Whenever there is a numerator in the form like (number) raised to something. Then Always try to bring denominator in the same form i.e. number (same as that of numerator) raised to something. So that the numbers can be easily cancelled out and our calculation becomes easier. |

Sazid said: (Sep 13, 2017) | |

432/12=36 so 12*36 or 12*6^2=432. |

Indrajith said: (Sep 24, 2017) | |

How can you know that 432=12x6^2? |

D Priya said: (Jan 23, 2018) | |

@Indrajith. They converted 432 in terms of multiples 12 & 6 so that it makes easy to cancel. |

Anusha said: (Jun 21, 2018) | |

Please give me the answer using BODMASS method. |

Kiara said: (Jun 22, 2018) | |

The correct answer is D. |

Anajana said: (Jul 1, 2018) | |

@Kiran. Wha is cyclicity? |

Aman said: (Jul 17, 2018) | |

Do HCF of 432. Then we get, (2^4)*(3^3) Which can be written as ( 2 * 3)*(2*3)*(2*2*3) or ( 6^2)*12. |

Katrina Kaiffff said: (Aug 31, 2018) | |

Thanks for this trick @Suba. |

Selva said: (Aug 31, 2018) | |

Thanks for the answer @Kiran Kumar. |

Mary said: (Sep 15, 2019) | |

Thanks all for explaining it. |

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