Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
33 comments Page 4 of 4.
Mahesh Patil said:
1 decade ago
Total Three digit numbers = 999-100+1 = 900
so numbers Divisible by 6 = 900 / 6 = 150 (Only Quotient ... don't consider the remainder)
so numbers Divisible by 6 = 900 / 6 = 150 (Only Quotient ... don't consider the remainder)
Vivek said:
1 decade ago
Adding the given three deghit it means =150
1+5+0/6=remander is 0
Hence if the adding number is not same in divedent and remander is not 0.
1+5+0/6=remander is 0
Hence if the adding number is not same in divedent and remander is not 0.
Ashok Kumar said:
1 decade ago
n=[(l-a)/d]+1
n=150
n=150
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