Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
34 comments Page 2 of 4.
Rohit said:
9 years ago
100 - 999 these are three digits no,
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
Tanu said:
9 years ago
Greatest 3 digit number that is divisible by 6 is 996 (q=166).
The smallest is 102(q=17).
Apply simple number rule to count number of values between 166 to 17,
i.e. 166-17+1=150.
Thus this gives you the number of 3 digits divisible by 6.
The smallest is 102(q=17).
Apply simple number rule to count number of values between 166 to 17,
i.e. 166-17+1=150.
Thus this gives you the number of 3 digits divisible by 6.
Damini said:
9 years ago
Write numbers from sequence 149 to 387 like 149150159.
How many time does 1 occur?
How many time does 1 occur?
Vatsal said:
8 years ago
Number is divided by 6 only when it is perfectly divided by 2 and 3 both.
So Only 150 is divided by both 2 and 3.
So Only 150 is divided by both 2 and 3.
Nithya said:
8 years ago
Divisiablity shortcut for 6 = the number should divide be both 2 & 3.
a. 149 / 2 = no because unit digit is odd.
b. 150 /2 = yes because unit digit ends in 0, then check for 3 -> 150 / 3 = 1+5+0 = 6 = 6/3 = 2, so answer is B.
a. 149 / 2 = no because unit digit is odd.
b. 150 /2 = yes because unit digit ends in 0, then check for 3 -> 150 / 3 = 1+5+0 = 6 = 6/3 = 2, so answer is B.
Tirtha said:
7 years ago
By taking the multiples of 2*3 for 6 we can operate the divisibility rule for this question.
As for 2, the ending digit should be 0, 2, 4, 6, 8 and for 3 sum of all the digit should be divisible by 3.
So, 150 is divisible by both 2 & 3. This is the correct answer.
As for 2, the ending digit should be 0, 2, 4, 6, 8 and for 3 sum of all the digit should be divisible by 3.
So, 150 is divisible by both 2 & 3. This is the correct answer.
Amar said:
6 years ago
Lowest 3 digit number which is divisible by 3 is 102.
Highest 3 digit number which is divisible by 3 is 999.
So as per the formula a+(n-1)d=l.
The answer will be 300.
Highest 3 digit number which is divisible by 3 is 999.
So as per the formula a+(n-1)d=l.
The answer will be 300.
Harpreet said:
1 decade ago
@Ashish total numbers divisible by 8 comes 112 & not 113.
Vivek said:
1 decade ago
Adding the given three deghit it means =150
1+5+0/6=remander is 0
Hence if the adding number is not same in divedent and remander is not 0.
1+5+0/6=remander is 0
Hence if the adding number is not same in divedent and remander is not 0.
Mahesh Patil said:
1 decade ago
Total Three digit numbers = 999-100+1 = 900
so numbers Divisible by 6 = 900 / 6 = 150 (Only Quotient ... don't consider the remainder)
so numbers Divisible by 6 = 900 / 6 = 150 (Only Quotient ... don't consider the remainder)
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