Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 32)
32.
How many 3-digit numbers are completely divisible 6 ?
Answer: Option
Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
Discussion:
33 comments Page 2 of 4.
Nithya said:
7 years ago
Divisiablity shortcut for 6 = the number should divide be both 2 & 3.
a. 149 / 2 = no because unit digit is odd.
b. 150 /2 = yes because unit digit ends in 0, then check for 3 -> 150 / 3 = 1+5+0 = 6 = 6/3 = 2, so answer is B.
a. 149 / 2 = no because unit digit is odd.
b. 150 /2 = yes because unit digit ends in 0, then check for 3 -> 150 / 3 = 1+5+0 = 6 = 6/3 = 2, so answer is B.
Vatsal said:
8 years ago
Number is divided by 6 only when it is perfectly divided by 2 and 3 both.
So Only 150 is divided by both 2 and 3.
So Only 150 is divided by both 2 and 3.
Damini said:
8 years ago
Write numbers from sequence 149 to 387 like 149150159.
How many time does 1 occur?
How many time does 1 occur?
Tanu said:
8 years ago
Greatest 3 digit number that is divisible by 6 is 996 (q=166).
The smallest is 102(q=17).
Apply simple number rule to count number of values between 166 to 17,
i.e. 166-17+1=150.
Thus this gives you the number of 3 digits divisible by 6.
The smallest is 102(q=17).
Apply simple number rule to count number of values between 166 to 17,
i.e. 166-17+1=150.
Thus this gives you the number of 3 digits divisible by 6.
Rohit said:
9 years ago
100 - 999 these are three digits no,
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
(last term - first term) + 1 = 900.
And divide 900 by 6 i. e. we obtained 150 is final answer.
Samir Das said:
9 years ago
Thanks for the answer. It's useful to me.
Rahul said:
9 years ago
Please give me a solution for "What is the sum of 3 digits number which is completely divisible by 3, then find the sum".
Ashok Kumar said:
1 decade ago
n=[(l-a)/d]+1
n=150
n=150
Joshua said:
1 decade ago
What if you try the formula for geometric sequence which is an = a1 x r^n-1.
Ayushi said:
1 decade ago
Divisibility rule of 6.
A no. is divisible by 6 if the no. is even and sum of digit is divisible by 3.
A no. is divisible by 6 if the no. is even and sum of digit is divisible by 3.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers