Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 46)
46.
In dividing a number by 585, a student employed the method of short division. He divided the number successively by 5, 9 and 13 (factors 585) and got the remainders 4, 8, 12 respectively. If he had divided the number by 585, the remainder would have been
Answer: Option
Explanation:
5 | x z = 13 x 1 + 12 = 25
--------------
9 | y - 4 y = 9 x z + 8 = 9 x 25 + 8 = 233
--------------
13| z - 8 x = 5 x y + 4 = 5 x 233 + 4 = 1169
--------------
| 1 -12
585) 1169 (1
585
---
584
---
Therefore, on dividing the number by 585, remainder = 584.
Discussion:
39 comments Page 3 of 4.
Naveen kumar v said:
4 years ago
Thanks @Manideep.
(1)
Niru said:
5 years ago
In successive division, last quotient is always 1.
Gowry said:
7 years ago
Thanks @Saurabh.
It is very simple to understand.
It is very simple to understand.
Aliya said:
7 years ago
Thanks @Ankit.
Sudip said:
4 years ago
Thanks @Manideep.
Tomo Lollen said:
2 years ago
Why we took 13 first and not 5? Please explain?
Chandru said:
1 decade ago
Thanks Ms. Arthy.
Vishnu said:
7 years ago
Thanks for the answer @Ankit Kumar.
Supriya karri said:
7 years ago
Nice explanation, Well said @Monica.
Suneetha said:
1 decade ago
@Dharamveer.
Divided the number successively by 5, 9 and 13 (factors 585) and got the remainders 4, 8, 12 respectively.
Dividers are 5, 9, 13.
Remainders are 4, 8, 12.
k = divider-remainder = 5-4 = 9-8 = 13-12 = 1.
Divided the number successively by 5, 9 and 13 (factors 585) and got the remainders 4, 8, 12 respectively.
Dividers are 5, 9, 13.
Remainders are 4, 8, 12.
k = divider-remainder = 5-4 = 9-8 = 13-12 = 1.
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