Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 46)
46.
In dividing a number by 585, a student employed the method of short division. He divided the number successively by 5, 9 and 13 (factors 585) and got the remainders 4, 8, 12 respectively. If he had divided the number by 585, the remainder would have been
24
144
292
584
Answer: Option
Explanation:
 5 | x                z = 13 x 1 + 12  = 25
 --------------
 9 | y - 4            y = 9 x z + 8  = 9 x 25 + 8  = 233
 --------------
 13| z - 8            x = 5 x y + 4  = 5 x 233 + 4  = 1169
 --------------
   | 1 -12
  
  585) 1169 (1
       585
       ---
       584
       ---
       
  Therefore, on dividing the number by 585, remainder = 584.     
Discussion:
39 comments Page 3 of 4.

Anujan said:   9 years ago
Thank you very much @Manideep.
(1)

SMcxlvii said:   9 years ago
Hope, my solution will be logical:

Suppose, the number is G.
According to the question:
G = 5a + 4 [where, a is an integer].
G = 9b + 8 [where, b is an integer].
G = 13c + 12 [where, c is an integer].

Now,
5a + 4 = G.
=> 5a + 5 - 1 = G.
=> 5(a + 1) = G + 1.

9b + 8 = G.
=> 9(b+) = G + 1.

13c + 12 = G.
=> 13(c + 1) = G+1.

Here, [5(a + 1)], [9(b + 1)], and [13(c + 1)] have same value [i.e: (G+1)].
So, the LCM of [5(a + 1)], [9(b + 1)], and [13(c + 1)] will also be (G + 1).

In other words,
LCM of [5(a + 1)], [9(b + 1)], and [13(c + 1)] = 585(a + 1)(b + 1)(c + 1).
So, 585(a + 1)(b + 1)(c + 1) = (G + 1).
Or, G = 585(a + 1)(b + 1)(c + 1) - 1.

Now, The number divided by 585.

=> G/585 = [585(a + 1)(b + 1)(c + 1) - 1]/585.
= [585(a + 1)(b + 1)(c + 1) - 585 + 584]/585.
= [{585(a + 1)(b + 1)(c + 1) - 1} + 584] = {(a + 1)(b + 1)(c + 1) - 1} + 584/585.

Surely {(a + 1)(b + 1)(c + 1) - 1} is an integer. So, the remainder is 584.
Then, the answer is 584.
(3)

Kalkesh said:   1 decade ago
Please any one explain me in easy way.
(1)

Siddharth said:   1 decade ago
@Saurabh.

It looked very simple. Thanks for making it look easy but can you explain what is the logic we have to keep in mind behind this.

Saurabh said:   1 decade ago
5-4=1
9-8=1
13-12=1

585-?=1
So the number is 584.
(5)

Manjeet SIngh said:   1 decade ago
@Maindeep.. How come assumed x=5a+4,a=9b+8,b=13c+12.
Because it should have been like this x=5a+4=9b+8=13c+12=585d+r.

Where r is the required remainder ...So there will be 3 equations to solve for a, b, c and x but unknown are for.(I am only confused about your assumption..please through some light on that).

Rahul said:   1 decade ago
@Sudhir

The question was to find the remainder when you divide the number by 585 but you used the method to calculate the number [required number =N*lcm(5,8,13)-1 ].

Can you explain what have you done ?

Ragul said:   1 decade ago
Divide 5 you get reminder as 4 and 9 you get 8 and 13 you get 12.

585+584 = 1169/5 = 4.

1+1+6+9 = 17/9 = 8.

Simply you get.

Rahul said:   1 decade ago
@Sudhir : How come we determine the value of N?

Surya said:   1 decade ago
How can we take the value of the last quotient as 1?


Post your comments here:

Your comments will be displayed after verification.