Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 131)
131.
A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be
Answer: Option
Explanation:
4 | x y = (5 x 1 + 4) = 9 -------- 5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37 -------- | 1 -4 Now, 37 when divided successively by 5 and 4, we get 5 | 37 --------- 4 | 7 - 2 --------- | 1 - 3 Respective remainders are 2 and 3.
Discussion:
22 comments Page 2 of 3.
Neeraj said:
6 years ago
4Q+1=n.
5q+4=Q.
n = 4(5q+4)+1 = 20q+17= 5 * 4q + 5 * 3 + 2.
Now n is devided by 5 so the remainder is 2.
And now devide 4q+3 by 4 so remainder is 3.
5q+4=Q.
n = 4(5q+4)+1 = 20q+17= 5 * 4q + 5 * 3 + 2.
Now n is devided by 5 so the remainder is 2.
And now devide 4q+3 by 4 so remainder is 3.
(7)
Gaurav said:
10 years ago
Here 29 is fit for this by hit and trail method when 29/4 give reminder 1 and when 29/5 gives reminder 4 so why 4, 1 is not answer.
Debashish Halder said:
1 decade ago
Earlier I mentioned (Y-1) which will be only (Y), that is when (X) is divided by 4 the result is (Y).
Ripa Roy said:
8 years ago
37/4=remainder 1.
Then how 1 - 3? I don't understand it, please explain it.
Then how 1 - 3? I don't understand it, please explain it.
Sarang said:
3 years ago
@All.
Dividend Formula:
Dividend = Divisor x Quotient + Remainder.
Dividend Formula:
Dividend = Divisor x Quotient + Remainder.
(2)
Tushar said:
1 decade ago
Divident=9, and next time it divided by 7 and 6. (not 5 and 4).
Surya Datta said:
11 months ago
37/4 reminder 1
But 37/5 reminder 2. Please explain to me.
But 37/5 reminder 2. Please explain to me.
(1)
RAKHI SHARMA said:
1 decade ago
I am unable to understand the solution.
Antara said:
1 decade ago
Answer should be 4 and 1.
Amy said:
1 decade ago
Someone, please explain.
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