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Aptitude - Numbers

Exercise : Numbers - General Questions
131.
A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be
1, 2
2, 3
3, 2
4, 1
Answer: Option
Explanation:
 4 | x            y = (5 x 1 + 4) = 9
 --------
 5 | y -1         x = (4 x y + 1) = (4 x 9 + 1) = 37
 --------
   | 1 -4

 Now, 37 when divided successively by 5 and 4, we get

 5 | 37
 ---------
 4 | 7 - 2
 ---------
   | 1 - 3
 
 Respective remainders are 2 and 3.
132.
8796 x 223 + 8796 x 77 = ?
2736900
2638800
2658560
2716740
None of these
Answer: Option
Explanation:
8796 x 223 + 8796 x 77 = 8796 x (223 + 77)   [Ref: By Distributive Law ]
= (8796 x 300)
= 2638800
133.
8988 ÷ 8 ÷ 4 = ?
4494
561.75
2247
280.875
None of these
Answer: Option
Explanation:
Given Exp. = 8988 x 1 x 1 = 2247 = 280.875
8 4 8
134.
287 x 287 + 269 x 269 - 2 x 287 x 269 = ?
534
446
354
324
None of these
Answer: Option
Explanation:
Given Exp. = a2 + b2 - 2ab, where a = 287 and b = 269
= (a - b)2 = (287 - 269)2
= (182)
= 324
135.
3 + 33 + 333 + 3.33 = ?
362.3
372.33
702.33
702
None of these
Answer: Option
Explanation:
    3
+  33
+ 333
+   3.33
  ------
  372.33
  ------
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