# Aptitude - Numbers

Exercise : Numbers - General Questions
131.
A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be
1, 2
2, 3
3, 2
4, 1
Explanation:
``` 4 | x            y = (5 x 1 + 4) = 9
--------
5 | y -1         x = (4 x y + 1) = (4 x 9 + 1) = 37
--------
| 1 -4

Now, 37 when divided successively by 5 and 4, we get

5 | 37
---------
4 | 7 - 2
---------
| 1 - 3

Respective remainders are 2 and 3.
```

132.
8796 x 223 + 8796 x 77 = ?
2736900
2638800
2658560
2716740
None of these
Explanation:
 8796 x 223 + 8796 x 77 = 8796 x (223 + 77)   [Ref: By Distributive Law ] = (8796 x 300) = 2638800

133.
8988 ÷ 8 ÷ 4 = ?
4494
561.75
2247
280.875
None of these
Explanation:
 Given Exp. = 8988 x 1 x 1 = 2247 = 280.875 8 4 8

134.
287 x 287 + 269 x 269 - 2 x 287 x 269 = ?
534
446
354
324
None of these
Explanation:
 Given Exp. = a2 + b2 - 2ab, where a = 287 and b = 269 = (a - b)2 = (287 - 269)2 = (182) = 324

135.
3 + 33 + 333 + 3.33 = ?
362.3
372.33
702.33
702
None of these
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