Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 131)
131.
A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be
Answer: Option
Explanation:
4 | x y = (5 x 1 + 4) = 9 -------- 5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37 -------- | 1 -4 Now, 37 when divided successively by 5 and 4, we get 5 | 37 --------- 4 | 7 - 2 --------- | 1 - 3 Respective remainders are 2 and 3.
Discussion:
22 comments Page 2 of 3.
Alam milan said:
9 years ago
Can you please tell the answer for this?
A number x when divided by 9 leaves a remainder 8. What is the remainder when we divide x^24 by 9?
A. 3
B. 2
C. 7
D. 1
A number x when divided by 9 leaves a remainder 8. What is the remainder when we divide x^24 by 9?
A. 3
B. 2
C. 7
D. 1
(1)
Gaurav said:
10 years ago
Here 29 is fit for this by hit and trail method when 29/4 give reminder 1 and when 29/5 gives reminder 4 so why 4, 1 is not answer.
Antara said:
1 decade ago
Answer should be 4 and 1.
Rohit Jain said:
1 decade ago
Let a number X which is divisible by 4 and 5 respective gives 1 and 4.
Step 1:
Now, first divide by 4. We take Y as dividend. When you divide X by 4 it gives remainder 1.
4 | X | Y.
______
1.
So X = 4 * Y + 1 --- equation(1).
Step 2:
Now, divide by 5. We take 1 as dividend because it divides completely. When you divide Y by 5 it gives only remainder 4.
5 | Y | 1.
______
4.
So Y = 5*1+4.
Step 3:
Y = 9.
And put this value in equation (1).
X = 4*9+1.
X = 37.
Step 4:
Now 37 divide by 5 and 4 respective it will gives 2 and 3.
Step 1:
Now, first divide by 4. We take Y as dividend. When you divide X by 4 it gives remainder 1.
4 | X | Y.
______
1.
So X = 4 * Y + 1 --- equation(1).
Step 2:
Now, divide by 5. We take 1 as dividend because it divides completely. When you divide Y by 5 it gives only remainder 4.
5 | Y | 1.
______
4.
So Y = 5*1+4.
Step 3:
Y = 9.
And put this value in equation (1).
X = 4*9+1.
X = 37.
Step 4:
Now 37 divide by 5 and 4 respective it will gives 2 and 3.
Akml said:
1 decade ago
When dividing a positive integer n by another positive integer D (divider) , we obtain a quotient Q, which is a non-negative integer and a remainder R, which is an integer such that 0\leq{R}<D. We can write n = DQ+R.
When dividing our number n by 4 we obtain a remainder of 1, so, if the quotient is some integer Q, we can write n = 4Q+1.
Now, dividing Q by 5, we obtain another quotient say q and remainder 4, thus we can write
Q = 5q+4.
It follows that n = 4(5q+4)+1 = 20q+17.
Since n = 20q+17 = 5(4q+3)+2, it means that when dividing n by 5 first, we get a quotient 4q+3 and remainder 2.
Then dividing 4q+3 by 4 we obviously obtain a remainder of 3.
When dividing our number n by 4 we obtain a remainder of 1, so, if the quotient is some integer Q, we can write n = 4Q+1.
Now, dividing Q by 5, we obtain another quotient say q and remainder 4, thus we can write
Q = 5q+4.
It follows that n = 4(5q+4)+1 = 20q+17.
Since n = 20q+17 = 5(4q+3)+2, it means that when dividing n by 5 first, we get a quotient 4q+3 and remainder 2.
Then dividing 4q+3 by 4 we obviously obtain a remainder of 3.
Tushar said:
1 decade ago
Divident=9, and next time it divided by 7 and 6. (not 5 and 4).
Thirupathi reddy said:
1 decade ago
Let a no x.
It is divided by 4 remainder is 1.
So x = 4*y + 1;
y = 5*z+ 4;( anther division).
Now,
x=4(5*z +4)+1= 20*z+17;
We can write above no.as
x=5(4*z +3)+2;
So above no gives remainder 2 when divided by 5. And then successive division gives remainder 3 from ( 4*z +3).
It is divided by 4 remainder is 1.
So x = 4*y + 1;
y = 5*z+ 4;( anther division).
Now,
x=4(5*z +4)+1= 20*z+17;
We can write above no.as
x=5(4*z +3)+2;
So above no gives remainder 2 when divided by 5. And then successive division gives remainder 3 from ( 4*z +3).
Jay said:
1 decade ago
Let the number be X. when it is divided by 4, remainder is 1 and quotient is Y(assume). now further when Y is divided by 5, remainder is 4 and quotient will be 1(successively divided). Now according to formula,
Y=(5*1)+4=9 and
X=(4*y)+1=(4*9)+1=37
So we got the values of X and Y..rest you can find out easily.
Y=(5*1)+4=9 and
X=(4*y)+1=(4*9)+1=37
So we got the values of X and Y..rest you can find out easily.
Debashish Halder said:
1 decade ago
Earlier I mentioned (Y-1) which will be only (Y), that is when (X) is divided by 4 the result is (Y).
Debashish Halder said:
1 decade ago
It is said that "divided SUCCESSIVELY by 4 and 5" .
SUCCESSIVE: Following one another
So from the given solution we see that at first any number (X) has been divided by 4 and then the result (Y-1) is divided by 5 .
SUCCESSIVE: Following one another
So from the given solution we see that at first any number (X) has been divided by 4 and then the result (Y-1) is divided by 5 .
(1)
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