Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
(216 + 1)
(216 - 1)
(7 x 223)
(296 + 1)
Answer: Option
Explanation:

Let 232 = x. Then, (232 + 1) = (x + 1).

Let (x + 1) be completely divisible by the natural number N. Then,

(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.

Discussion:
137 comments Page 6 of 14.

Deva said:   8 years ago
I don't understand the solution. Please, someone explain me.

Saruu said:   9 years ago
Can anyone give a simple method to explain this?

Sajid said:   9 years ago
I don't understand. Please, someone explain me.

Apsana said:   9 years ago
I can't understand this please explain this in a simply way.

Sajal said:   9 years ago
I didn't understand the last step. Please explain it.

Pranshu said:   9 years ago
Why not option A? Explain.

Shirisha said:   9 years ago
I understand this. But I want simple method.

Mahalakshmi said:   9 years ago
I can't understand please explain again in a simple way.

Owais Majeed said:   9 years ago
It is written in question no should be completely divisible.

For that number should be greater than given number i.e. 2^32+1.

Ex 1/2 = 0.5 (not completely divisible).

4/2 = 2 (completely divisible).

So option A, B, C all three numbers are less than given number 2^32 +1.

Now come on option D = 2^96+1. Clearly shows number is greater than 2^32+1.

This is what up to which some logic can b made.

Rest how it is possible to refer to given explanation of the question.

Thanks.

Karthika said:   9 years ago
I could not understand the problem please explain me easily.


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