Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 3)
3.
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer: Option
Explanation:
Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Discussion:
138 comments Page 14 of 14.
Mickeey said:
2 decades ago
this is some what called as hit and trial method, you have to try the options which are similar to the value (2^32+1) in the question. remaining, you can easily eliminate by seeing.
in the above, options A and D are similar to the expression given in the question.
suppose the given four options are similar, you have to try all...
this is also called as trial and error method...
in the above, options A and D are similar to the expression given in the question.
suppose the given four options are similar, you have to try all...
this is also called as trial and error method...
Mohsin said:
2 decades ago
Ohh Its confusing !!!!!
I cant understand y take (2^96+1)??????????????????
I cant understand y take (2^96+1)??????????????????
Priya said:
2 decades ago
When we make 2^32 is X,
We try to simplify to get the answer split 2^96 = 2^(32X3)
so it is = X^3
When using the formula for X^3+1, we can identify that number is divisible by 2^32
We try to simplify to get the answer split 2^96 = 2^(32X3)
so it is = X^3
When using the formula for X^3+1, we can identify that number is divisible by 2^32
Divya said:
2 decades ago
I can't to understand your explanation. Can you explain clearly and basically................
A.Athiban Sakthivel said:
2 decades ago
But its too complicated procedure.
Is not there more simple procedure to solve this problem?
Is not there more simple procedure to solve this problem?
Rahul said:
2 decades ago
Hi Dear,
2^32^3 here multiplication of power will take place. So 32x3 = 96 Ok.
2^32^3 here multiplication of power will take place. So 32x3 = 96 Ok.
Devi said:
2 decades ago
I cannot understand how replace (2^96+1) = [ (2^32) ^3].
Pavi said:
2 decades ago
I cannot understand, please explain.
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