Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 73)
73.
(xn - an) is completely divisible by (x - a), when
Answer: Option
Explanation:
For every natural number n, (xn - an) is completely divisible by (x - a).
Discussion:
6 comments Page 1 of 1.
Sumon said:
2 decades ago
which numbers are natural number? Please explain.
Navneet S said:
1 decade ago
can someone explain it ?
Ally said:
1 decade ago
@Suman: In a collection (or set) of objects (or elements), the act of determining the number of objects present is called counting. The numbers thus obtained are called the counting numbers or natural numbers (1, 2, 3, ). For an empty set, no object is present, and the count yields the number 0, which, appended to the natural numbers, produces what are known as the whole numbers.
Preetpal singh said:
4 years ago
@Navneet
Recall the formula (a^2 - b^2) here n is 2 which is even, this equation is equal to (a+b)(a-b) hence we can see it is divisible by (a+b) and (a-b).
Recall the formula (a^2 - b^2) here n is 2 which is even, this equation is equal to (a+b)(a-b) hence we can see it is divisible by (a+b) and (a-b).
Abhijeet Bhattacharya said:
10 months ago
Natural Numbers are 1,2,3,4,........... so on
(i) when n = 1 , (xⁿ - aⁿ) = (x - a) which is divisible by (x - a)
(ii) when n = 2, (xⁿ - aⁿ) = x² - a² = (x - a)(x + a) which is divisible by (x-a)
(iii) when n = 3, (xⁿ - aⁿ) = x³ - a³ = (x-a)(x²+ax+a²) which is divisible by (x-a)
other numbers like 4 6 8 can be solved similarly like the (ii)
other number like 5 7 8 can be solved similarly like the (iii)
(i) when n = 1 , (xⁿ - aⁿ) = (x - a) which is divisible by (x - a)
(ii) when n = 2, (xⁿ - aⁿ) = x² - a² = (x - a)(x + a) which is divisible by (x-a)
(iii) when n = 3, (xⁿ - aⁿ) = x³ - a³ = (x-a)(x²+ax+a²) which is divisible by (x-a)
other numbers like 4 6 8 can be solved similarly like the (ii)
other number like 5 7 8 can be solved similarly like the (iii)
Abhijeet said:
9 months ago
Natural Numbers are 1,2,3,4,........... so on;
(i) when n = 1 , (xⁿ - aⁿ) = (x - a) which is divisible by (x - a).
(ii) when n = 2, (xⁿ - aⁿ) = x² - a² = (x - a)(x + a) which is divisible by (x-a).
(iii) when n = 3, (xⁿ - aⁿ) = x³ - a³ = (x-a)(x²+ax+a²) which is divisible by (x-a).
Here other numbers like 4 6 8 can be solved similarly like the (ii).
And other numbers like 5 7 8 can be solved similarly like the (iii).
(i) when n = 1 , (xⁿ - aⁿ) = (x - a) which is divisible by (x - a).
(ii) when n = 2, (xⁿ - aⁿ) = x² - a² = (x - a)(x + a) which is divisible by (x-a).
(iii) when n = 3, (xⁿ - aⁿ) = x³ - a³ = (x-a)(x²+ax+a²) which is divisible by (x-a).
Here other numbers like 4 6 8 can be solved similarly like the (ii).
And other numbers like 5 7 8 can be solved similarly like the (iii).
(1)
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