Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 30)
30.
What will be remainder when (6767 + 67) is divided by 68 ?
Answer: Option
Explanation:
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
Discussion:
70 comments Page 5 of 7.
Nivas said:
9 years ago
The formula is a^n + b^n is divisible by a + b if n is odd.
Minaxi said:
1 decade ago
67((i^67+1)) = 67(1+1) => 67*2 = 134 => 134-68 = 66.
Vasanthi said:
6 years ago
I didn't understand the concept. Please explain it for me.
(2)
Sanjay said:
10 years ago
Simple method of this problem is 67+67 = 134-68 = 66.
Deepak Parmar said:
7 years ago
How to find unit digit of any number? Please tell me.
Aakash said:
7 years ago
Please anyone explain clearly. I can't understand.
Mega said:
1 decade ago
Cannot understand the concept please xplain.
Wesly said:
6 years ago
Thanks for the clear explanation, @Padmaja.
Yogesh said:
1 decade ago
When x pow even then. what's the procedure?
Reshma said:
9 years ago
What would be the solution when n is even?
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