Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 30)
30.
What will be remainder when (6767 + 67) is divided by 68 ?
Answer: Option
Explanation:
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
Discussion:
70 comments Page 1 of 7.
Narendra said:
1 decade ago
Please suggest me another method.
Shyni M said:
1 decade ago
Cant understand the concept .
Nik said:
1 decade ago
Any other method please.
Ankush said:
1 decade ago
Simplify please.
Mega said:
1 decade ago
Cannot understand the concept please xplain.
Jpragash said:
1 decade ago
Not understand.
Mahi said:
1 decade ago
Simply if you got dis situation do as follow
jus 67*2=134
if u hav any doubt check wid another simple example as follow
3pwr3+3 check wedr it is divisible with 4 r not
by solving in normal way we will get as follow
3pwr3+3 you will get 30. divide 30 with 4 you will get 2 reminder
according to our procedure
3*2=6
So better to go this way guys.
jus 67*2=134
68)134(1
68
---
66
if u hav any doubt check wid another simple example as follow
3pwr3+3 check wedr it is divisible with 4 r not
by solving in normal way we will get as follow
3pwr3+3 you will get 30. divide 30 with 4 you will get 2 reminder
according to our procedure
3*2=6
4)6(1
4
--
2
So better to go this way guys.
(3)
Yogesh said:
1 decade ago
When x pow even then. what's the procedure?
Deepak said:
1 decade ago
Find out unity digit of 67^67....i e unit digit is 3
n 3+67=70
and when divide by 68 remainder 2...ie 68-2=66
n 3+67=70
and when divide by 68 remainder 2...ie 68-2=66
Ravi said:
1 decade ago
I support deepak but in additional I would like you to know of this 67^67 units digit is to b found out. By cyclicity of numbers concept 67/4 remainder 3. So units digit is units digit of 7^3=**3 so adding 3+67=70.
When divide by 68 remainder 2. Ie 68-2=66.
When divide by 68 remainder 2. Ie 68-2=66.
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