Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 30)
30.
What will be remainder when (6767 + 67) is divided by 68 ?
1
63
66
67
Answer: Option
Explanation:

(xn + 1) will be divisible by (x + 1) only when n is odd.

(6767 + 1) will be divisible by (67 + 1)

(6767 + 1) + 66, when divided by 68 will give 66 as remainder.

Discussion:
70 comments Page 4 of 7.

Deepak Parmar said:   7 years ago
How to find unit digit of any number? Please tell me.

Raji said:   7 years ago
(x^n+1) is divisible by (x+1), if not is odd.
So, ( 67^67+1) is divisible by 68 (i.e.)67 + 1.
(67^67+1)÷68 provides remainder 0.

Given: (67^67+67)÷68 ->(67^67 + 1 + 66)÷68.
->provides remainder 66.

Aakash said:   7 years ago
Please anyone explain clearly. I can't understand.

Mamatha said:   6 years ago
@Sivaram.

It was very helpful. Thanks.

Paveek said:   9 years ago
Thank you @Anuj.

Random retard said:   6 years ago
Thanks to all the good souls who took time to explain the answer.

Prakash said:   4 years ago
Thank you so much @Mahi.

Clinton said:   3 months ago
@Ummar.

Please elaborate your answer.

MADHU said:   1 decade ago
If (67^67 + 1) + 66, when divided by 68 will give 66 as remainder.

Again if you use 63 instead of 67 (67^67 + 1) + 63, when divided by 68 will give 63 as remainder.

Same goes with (67^67 + 1) + 67, when divided by 68 will give 67 as remainder.

WHAT LOGIC IS THERE? AND THE QUESTION IS DIRECTLY MENTION THAT (67^67+1) +67 IS DIVIDE BY 68.

FIND THE REMAINDER THEN WHY ARE WE ADDING EXTRA NUMBERS ON IT AGAIN?

Shyni M said:   1 decade ago
Cant understand the concept .


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