Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 30)
30.
What will be remainder when (6767 + 67) is divided by 68 ?
Answer: Option
Explanation:
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
Discussion:
70 comments Page 4 of 7.
Kanak said:
8 years ago
22 + 2 divided by 3.
= 4 + 2,
= 6.
so when 6 divided by 3 then remainder = 0.
So by doing calculations like this we can get:
22 + 2 divided by 3 then remainder = 0.
33 + 3 divided by 4 then remainder = 2.
44 + 4 divided by 5 then remainder = 0.
55 + 5 divided by 6 then remainder = 4.
So by observing above examples we can say;
xx + x is divided by (x+1) then the remainder is (x-1) where x is odd number.
So, now we can say when 6767 + 67 is divided by 68 then remainder is 66.
= 4 + 2,
= 6.
so when 6 divided by 3 then remainder = 0.
So by doing calculations like this we can get:
22 + 2 divided by 3 then remainder = 0.
33 + 3 divided by 4 then remainder = 2.
44 + 4 divided by 5 then remainder = 0.
55 + 5 divided by 6 then remainder = 4.
So by observing above examples we can say;
xx + x is divided by (x+1) then the remainder is (x-1) where x is odd number.
So, now we can say when 6767 + 67 is divided by 68 then remainder is 66.
(1)
NIranjani said:
9 years ago
(67^67+67)/68 = 67^67/68 + 67/68.
= (67+67)/68.
a^n/(a+1) = a when n is odd.
= 66(ans),
= 1 when n is even.
= (67+67)/68.
a^n/(a+1) = a when n is odd.
= 66(ans),
= 1 when n is even.
Jitendra gujjar said:
9 years ago
Is there any Short trick?
Pawas said:
9 years ago
a^b is a raise to the power b.
To understand this question we must take a simpler example.
for ex- (3x3)/4
3 = (4-1),
Therefore the question becomes
(4-1)(4-1)/4.
On multiplying (4^2-4-4+1)/4
Note that all the terms in the expansion are completely divisible by 4 except 1.hence Remainder will be 1.
Now take expression for example- 3x3x3 /4.
again (4-1)(4-1)(4-1)/4,
(4^2-4-4+1)(4-1) / 4,
= 4x(4^2-4-4+1)-1x(4^2-4-4+1),
= 4x(4^2-4-4+1) + (-4^2)+4+4-1.
Here the first term is divisible by 4 and in the second term after multiplication by -1 only +1 remains which is not divisible.
Carrying out this process only 1 will remain as the remainder and its sign will depend on the power of the numerator. when the power of 3 was 2, the remainder was +1 and when the power was 3, the remainder was -1.
This means when the power of numerator is odd, -1 will remain and when the power will be even, +1 will remain.
Using this in our example:- (67^67)/68.
-1 will remain because the power of the numerator is odd.
and we also have a +67 in the numerator. therefore, total remaining in the numerator is -1+67 = 66. Which is the remainder and our answer.
To understand this question we must take a simpler example.
for ex- (3x3)/4
3 = (4-1),
Therefore the question becomes
(4-1)(4-1)/4.
On multiplying (4^2-4-4+1)/4
Note that all the terms in the expansion are completely divisible by 4 except 1.hence Remainder will be 1.
Now take expression for example- 3x3x3 /4.
again (4-1)(4-1)(4-1)/4,
(4^2-4-4+1)(4-1) / 4,
= 4x(4^2-4-4+1)-1x(4^2-4-4+1),
= 4x(4^2-4-4+1) + (-4^2)+4+4-1.
Here the first term is divisible by 4 and in the second term after multiplication by -1 only +1 remains which is not divisible.
Carrying out this process only 1 will remain as the remainder and its sign will depend on the power of the numerator. when the power of 3 was 2, the remainder was +1 and when the power was 3, the remainder was -1.
This means when the power of numerator is odd, -1 will remain and when the power will be even, +1 will remain.
Using this in our example:- (67^67)/68.
-1 will remain because the power of the numerator is odd.
and we also have a +67 in the numerator. therefore, total remaining in the numerator is -1+67 = 66. Which is the remainder and our answer.
(1)
Paveek said:
9 years ago
Thank you @Anuj.
Shru said:
9 years ago
It's very easy, Thank you @Mahi.
Sharanya said:
9 years ago
Give more clarity about this question.
Ambika said:
9 years ago
Why do we subtract 2 from 68?
Nivas said:
9 years ago
The formula is a^n + b^n is divisible by a + b if n is odd.
Meghana said:
9 years ago
Why do we subtract 2 the remainder from 68, can anyone explain this?
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