Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 28)
28.
If n is a natural number, then (6n2 + 6n) is always divisible by:
Answer: Option
Explanation:
(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
Discussion:
27 comments Page 3 of 3.
NIRANJAN said:
7 years ago
If 46N is divisible by 18 then what is the value of N?
Emi said:
1 decade ago
What is mean product of even, odd is always even?
Vishnu said:
1 decade ago
Hey I don't understand this problem please help!
Karma said:
1 decade ago
I don't understand this problem please help.
Prudvi said:
8 years ago
The numbers should be 6, 12, 18, 24.
Sandeep said:
1 decade ago
Product of even, odd is always even.
Akhil said:
1 decade ago
How is n(n+1) proved an even numer?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers