Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 28)
28.
If n is a natural number, then (6n2 + 6n) is always divisible by:
Answer: Option
Explanation:
(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
Discussion:
27 comments Page 2 of 3.
Priya said:
1 decade ago
But, If we put n=9 in 6n2+6n.
i.e, 6(9)2+6(9)
= 6(81)+54
= 486+54
= 540
But, here 540 is not divisible by 12.
So, how?
i.e, 6(9)2+6(9)
= 6(81)+54
= 486+54
= 540
But, here 540 is not divisible by 12.
So, how?
Deepak maurya said:
1 decade ago
Given expression is (6n^2 + 6n) = 6n(n+1).
Put n = 1.
Then,
= 6n(n+1).
= 6(1)*(1+1)
= 6*2 = 12.
Now 12 can be divided by 6 and 12.
Put n = 1.
Then,
= 6n(n+1).
= 6(1)*(1+1)
= 6*2 = 12.
Now 12 can be divided by 6 and 12.
Shruti said:
3 years ago
If we assume that n = 1.
Then,
6n^2+6n,
6*1*1+6*1 = 12,
So from the given options, 6 and 12 is always divisible.
Then,
6n^2+6n,
6*1*1+6*1 = 12,
So from the given options, 6 and 12 is always divisible.
(3)
Sid said:
7 years ago
@Niranjan.
It would be 8,
because 18x25=450,
And then so, 18x26=468,
So, N would be 8.
It would be 8,
because 18x25=450,
And then so, 18x26=468,
So, N would be 8.
Onkar said:
5 years ago
When N is odd. Then it's not divisible by 12.
So, it's divisible by only 6.
So, it's divisible by only 6.
K.pavan said:
1 decade ago
ELIMINATION METHOD...
PUT n=1. we get 12.
12 is divisible by both 12, 6.
PUT n=1. we get 12.
12 is divisible by both 12, 6.
Hussain said:
1 decade ago
Who told you that 540 is not divisible by 12?
540/12 = 45.
540/12 = 45.
VISITHRA .S said:
8 years ago
I do not understand this problem. Please explain in detail.
Jayaprasath said:
8 years ago
Substitute any number for n.
It will become even number.
It will become even number.
Veer said:
9 years ago
Some books write it wrongly 6n2+6n instead of 6n^2 + 6n.
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