Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 81)
81.
The difference of the squares of two consecutive even integers is divisible by which of the following integers ?
Answer: Option
Explanation:
Let the two consecutive even integers be 2n and (2n + 2). Then,
(2n + 2)2 = (2n + 2 + 2n)(2n + 2 - 2n)
= 2(4n + 2)
= 4(2n + 1), which is divisible by 4.
Discussion:
15 comments Page 2 of 2.
Sreemoy said:
5 years ago
-n +2>0 and 2n >4 the number of integer n satisfying.
Marthandan said:
1 decade ago
Please explain (2n+2) ^2 = (2n+2+2n) (2n+2-2n).
Balaji said:
1 decade ago
Please explain (2n+2) ^2 = (2n+2+2n) (2n+2-2n).
Kavitha said:
9 years ago
Agree @Prabhu.
a^2 - b^2 = (a + b)(a - b).
a^2 - b^2 = (a + b)(a - b).
Naveen said:
1 decade ago
Here missing it should be (2n+2)^2-(2n)^2
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