Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 104)
104.
On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is:
47619
47719
48619
47649
Answer: Option
Explanation:

By hit and trial, we find that

47619 x 7 = 333333.

Discussion:
10 comments Page 1 of 1.

Vicky said:   10 months ago
@All.

How to found 3s was 6 digit 333333? Anyone, explain this

Vishnu vardhan voleti said:   6 years ago
Its simple.
4+7+6+1+9=(27)2+7=9.
9x7(63) 6+3=9.
(1)

MANSURI said:   6 years ago
Take a string of 3's e.g. 333333....

Divide this till remainder becomes zero.
So, Answer is 47619.
(2)

Siri said:   6 years ago
Please explain it clearly.
(1)

Durga moksha said:   7 years ago
What is meant by hit and trial method?

Can anyone explain it?
(1)

Anjan said:   10 years ago
No need for hit and trial.

From the option we can say that the number each of whose digits are 3 will be 333333.

So divide it by 7 and you will get the answer.
(1)

Narottam tiwari said:   1 decade ago
Simply you write down 3 each time and divide by 7. At a time you will get the desired solution. Like 33/7 = now remainder is 53/7 (added another 3) now remainder is 43/7 (added another 3).

And so on at a point the number would be divisible and that's your answer. In simple way = 333333/7 = 47619.

Diksha said:   1 decade ago
There is not much time to calculate each and everything, I am still not understand. Please give the proper solution.

Tirthesh said:   1 decade ago
There is no hit and trial the solution is simple.

By multiplying all the option by 7 we will get a 6 digit no then it must be 333333.

So answer is 333333/7 = 47619.
(1)

Srinivasane said:   1 decade ago
The question is product is all 3's divide that by 7 gives the answer.

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