Aptitude - Numbers - Discussion

Let us suppose that, 2272=x+r and 875=y+r then x-y=2272-875=1397 this is the difference between the two numbers. This 1397 should be completely divisible by divisor (as 1397 is free from remainder and is the actual difference between the (2272-r) & (875-r) hence should be completely divisible by the divisor. Now 1397=11*127. As divisor should be a 3 digit number, so 127 can be considered as the remainder which fulfills our criteria. Therefore sum of digits=1+2+7=10.

hello buddys!

I think the following could be one of the methods:

we know, dividend=divisor*quosent+remainder
divisor=d,quosen=1(if not given assume it to be 1)+remainder=r

so, 2272=d*1+r
875=d*1+r
since remainder are equal from the question,
r=2272-d -equ1
r=875-d -equ2
equ=equ2

2272-d=875-d
we get 1397 this our N.and sum of the digits 20.
becoz we r dealing with two equ same remainder, so divide it by 2.
i.e 20/2= 10.

I dont know whether is it wright but any ways am getting the answer.

Sorry ! I couldn't get it.......... please explain it in another way.

Any other easy way?