Aptitude - Numbers - Discussion
Discussion Forum : Numbers - General Questions (Q.No. 58)
58.
On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
Answer: Option
Explanation:
Clearly, (2272 - 875) = 1397, is exactly divisible by N.
Now, 1397 = 11 x 127
The required 3-digit number is 127, the sum of whose digits is 10.
Discussion:
34 comments Page 3 of 4.
Kptel said:
9 years ago
Thanks @Sravan.
Jatin said:
10 years ago
Here is an shortcut:
= 2+2+7+2-8+7+5 = 7.
= 7+3 = 10.
= 2+2+7+2-8+7+5 = 7.
= 7+3 = 10.
Soumili said:
1 decade ago
I did not understand.
Sravan said:
1 decade ago
Consider that if two nos if divided by a same divisor gets same reminders. Then the difference between the nos will be exactly divisible by the divisor.
For example:
5/2 remainder is 1.
9/2 remainder is 1.
9-5 = 4, which is exactly divisible by 2.
For example:
5/2 remainder is 1.
9/2 remainder is 1.
9-5 = 4, which is exactly divisible by 2.
Janaki said:
1 decade ago
Why we are factorizing 1397?
Sneha said:
1 decade ago
As 2272 and 875 is divided by same number(x), obviously they are the factors of (x).
So when we subtract 2272-875 = 1397.
Now, this 1397 is also factor of (x).
Now just simply divide 1397 by options given in number.
i.e. (10, 11, 12, 13) then we find that 11 is the only number divisible by 1397.
Hence 1397/11 = 127 i.e. 11*127 = 1397.
1+2+7 = 10.
So when we subtract 2272-875 = 1397.
Now, this 1397 is also factor of (x).
Now just simply divide 1397 by options given in number.
i.e. (10, 11, 12, 13) then we find that 11 is the only number divisible by 1397.
Hence 1397/11 = 127 i.e. 11*127 = 1397.
1+2+7 = 10.
Himanshu said:
1 decade ago
@Shreyank by adding the digits of 127 (i e. , the 3-digit number).
Shreyank said:
1 decade ago
We can 11*127 so we can get 1397.
But how we get 10.
But how we get 10.
Geetha said:
1 decade ago
Please explain me how you get 1397 is 11 & 127?
Sanjali Jha said:
1 decade ago
Lets take the remainder as x,
2272-x is the quotient which is divisible by n.
875-x is the quotient which is divisible by n.
[2272-x]-[875-x] = a number which is divisible by n.
= 1397.
The factors of 1397 are 11 and 127.
127 is n as it is a three digit number and fills all conditions.
1+2+7 = 10.
10 is the answer.
2272-x is the quotient which is divisible by n.
875-x is the quotient which is divisible by n.
[2272-x]-[875-x] = a number which is divisible by n.
= 1397.
The factors of 1397 are 11 and 127.
127 is n as it is a three digit number and fills all conditions.
1+2+7 = 10.
10 is the answer.
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